The solution for this problem is computed by through this formula, F = kQq / d²Plugging in the given values above, we can now compute for the answer.
F = 8.98755e9N·m²/C² * -(7e-6C)² / (0.03m)² = -489N, the negative sign denotes attraction.

4 0

2 years ago

A large pot is placed on a stove and 1.2 kg of water at 14°C is added to the pot. The temperature of the water is raised evenly

CaHeK987 [17]

Answer:

100°heat

Explanation:

since when i calculate this and that, the answer is 100° heat.

sorry if it is inconvenient

3 0

2 years ago

A 9.0-kg bowling ball on a horizontal, frictionless surface experiences a net force of 6.0 n. what will be its acceleration?

Vladimir [108]

This question involves the concepts of Newton's Second Law of Motion.

The acceleration of the bowling ball will be "0.67 m/s²".

<h3>Newton's Second Law of Motion</h3>

According to Newton's Second Law of Motion, when an unbalanced force is applied on an object, it produces an acceleration in it, in the direction of the applied force. This acceleration is directly proportional to the force applied and inversely proportional to the mass of the object. Mathematically,

$F=ma\\\\a=\frac{F}{m}$

where,

a = acceleration = ?
F = Magnitude of the applied force = 6 N
m = Mass of the ball = 9 kg

Therefore,

$a=\frac{6\ N}{9\ kg}$

a = 0.67 m/s²

Learn more about Newton's Second Law of Motion here:

brainly.com/question/13447525

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7 0

2 years ago