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If is an even function, then
. In this case,
.
This is because an even function is symmetric about the . Hence the outputs of a negative x-value and a positive x-value are the same.
The correct option is the first option.
Since the graph is even, the outputs of a negative x-value and a positive x-value are the same.
The Factorization of 121b⁴ − 49 is (11b^2 + 7)(11b^2 - 7).
The equation 121b⁴ − 49
To find the Factorization of 121b⁴ − 49.
<h3>What is the factor of a^2-b^2?</h3>
The factor of a^2-b^2 is (a+b)(a-b)
We have write the given equation in the form of a^2-b^2
Therefore the factor of the 121b^4 − 49 is (11b^2 + 7)(11b^2 - 7).
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