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kenny6666 [7]
3 years ago
6

The icon indicates an exercise designed to provide practice using a calculator. solve y-6= -14

Mathematics
2 answers:
Anastaziya [24]3 years ago
6 0
Y-6=-14
+6 +6
y=-8
.....
nlexa [21]3 years ago
3 0
The correct answer is y = -8.

y - 6 = -14   Given
y = -8   Add 6 to both sides; keep in mind that when you add to a negative, the number appears to become smaller (-4 + 1 = -3)

Therefore, y = -8.

Hope this helps!
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Write each power as a product of the Same factor then find the value 1. 4^3 2. 2^6 3. 8^4 4. 12^2​
qwelly [4]

Answer:

15^3=15×15×15=3375

0^4=0×0×0×0=0

5^5=5×5×5×5×5=3125

3.5^2=3.5×3.5=12.25

6^5=6×6×6×6×6=7776

7^4=7×7×7×7=2401

1^8=1×1×1×1×1×1×1×1=1

2.5^3=2.5×2.5×2.5=15.625

Step-by-step explanation:

7 0
3 years ago
A gardener has 27 pansies and 36 daisies he ants an equal number of each type of flower in each row what is the greatest possibl
Komok [63]
There are 27 pansies.
The possible rows that will contain equal numbers of pansies are
1 row, 27 pansies in the row, or
3 rows, 9 pansies per row, or
9 rows, 3 pansies per row.

There are 36 daisies.
The possible rows that will contain equal numbers of daisies are
1 row, 36 daisies in the row,
2 rows, 18 daisies per row, or
3 rows, 12 daisies per row, or
4 rows, 9 daisies per row, or
6 rows, 6  daisies per row, or
9 rows, 4  daisies per row, or
12 rows, 3 daisies per row, or
18  rows, 2 daisies per row.

The only common row combination is 3 rows, with 9 pansies and 12 daisies per row.

Answer:  9 pansies in each row.
5 0
4 years ago
Pls help me ASAP I have other homework to do and I don’t have time for this. It also detects if it’s right or wrong:(
Tems11 [23]
The answer is B. 5 hours.
7 0
3 years ago
Read 2 more answers
Story Problem
jok3333 [9.3K]

Answer:

245.10

Step-by-step explanation:

You have to multiply $6.45 by 38

8 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%5Cleft%28%5Csqrt%7B3%7D%2B4%5Cright%29%5Cleft%281%2B%5Csqrt%7B3%7D%5Cright%29" id="TexFormula
kirza4 [7]

Answer:

\huge\boxed{\sf 7 + 5\sqrt{3} }

Step-by-step explanation:

(\sqrt{3} +4)(1+\sqrt{3})\\\\= \sqrt{3}(1+\sqrt{3} )+4(1+\sqrt{3})\\\\= \sqrt{3} + (\sqrt{3} )^2 + 4 + 4\sqrt{3} \\\\= \sqrt{3} + 3+4+4\sqrt{3}  \\\\= 7 + \sqrt{3}  + 4\sqrt{3} \\\\Take \ \sqrt{3} \ common\\\\= 7 + \sqrt{3} (1+4)\\\\= 7 + \sqrt{3}(5)\\\\= 7 + 5\sqrt{3} \\\\\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
4 0
2 years ago
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