1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
mel-nik [20]
2 years ago
5

Converting 67 m•s¹ to km•h¹​

Physics
1 answer:
IrinaVladis [17]2 years ago
5 0

Answer:

Hola como estás ehord as ve hi5 ido

zdry8wygf

fje di oo0008t aquí 1gvu txdc

You might be interested in
Which of the following types of electromagnetic radiation has the lowest energy?
Fofino [41]

UV rays have the lowest energy, (highest wavelengths)

8 0
2 years ago
Which statement correctly compares the valence electrons for atoms of francium (Fr) and barium (Ba)?
Sauron [17]

Answer:

Francium has fewer valence electrons, but they are in a higher energy level

8 0
3 years ago
Read 2 more answers
The robot arm is elevating and extending simultaneously. At a given instant, θ = 30°, ˙ θ = 10 deg / s = constant θ˙=10 deg/s=co
motikmotik

Explanation:

The position vector r:

\overrightarrow{r(t)}=lcos\theta\hat{i}+lsin\theta\hat{j}

The velocity vector v:

\overrightarrow{v(t)}=\overrightarrow{\frac{dr}{dt}}=\dot{l}cos\theta-lsin\theta\dot{\theta}\hat{i}+\dot{l}sin\theta+lcos\theta\dot{\theta}\hat{j}

The acceleration vector a:

\overrightarrow{a(t)}}=cos\theta(\ddot{l}-l\dot{\theta}^2)-sin\theta(2\dot{l}\dot{\theta}+l\ddot{\theta})\hat{i}+cos\theta(2\dot{l}\dot{\theta}+l\ddot{\theta})+sin\theta(\ddot{l}-l\dot{\theta}^2)\hat{j}

\overrightarrow{v(t)}=0.13\hat{i}+0.18\hat{j}

\overrightarrow{a(t)}}=-0.3\hat{i}-0.1\hat{j}

5 0
3 years ago
A spectral line from a star is observed to have a wavelength of 656.5 nm. The rest wavelength of this line is 656.8 nm. (a) What
nignag [31]

Answer:

speed of star is  1.37 × 10^{5} m/s

it is approaching to earth because wavelength of star is decreasing than rest

if emit same wavelength it does not move anywhere

it will remain steady condition with respect earth

Explanation:

given data

wavelength = 656.5 nm

rest wavelength = 656.8 nm

to find out

the speed of the star , is it approaching

solution

we know here equation that is

wavelength shift / wavelength at rest  = velocity of source / speed of light

so put all value and find

velocity of source = 3 × 10^{-9} × 3 × 10^{8} / 656.8 × 10^{-9}

velocity of source star = 1.37 × 10^{5} m/s

and

it is approaching to earth because wavelength of star is decreasing than rest

and

if emit same wavelength it does not move anywhere

it will remain steady condition with respect earth

6 0
3 years ago
If yall friend me ill give lots of points like this in the future
Ne4ueva [31]

Answer:

ok......................

3 0
2 years ago
Other questions:
  • A net force of 16 N causes a mass to accelerate at a rate of 5 m/s^2. Determine the mass.
    15·1 answer
  • When heating water, during what temperature range will the temperature cease to change for some time?
    14·2 answers
  • in an experiment, all participants receive a treatment but those in the control group recieves a false treatments
    14·1 answer
  • Kinetic and potential energies of a roller coaster I'm doing a portfolio
    12·1 answer
  • 5. What is the percent composition of sulfur in H2SO4?
    5·2 answers
  • A slower moving car is traveling behind a faster moving bus. The velocities of the two vehicles are: vCG = velocity of the Car r
    12·1 answer
  • A sound wave has a wavelength of 0.450 meters. If its speed in cold air is 330 meters/second, what is the wave's frequency?
    7·2 answers
  • A sound has 13 crests and 15 troughs in 3 seconds. When the second crest is produced the first is 2cm away from the source? Calc
    14·1 answer
  • (02.09 MC) An object starts at rest. Its acceleration over 30 seconds is shown in the graph below: An acceleration versus time g
    8·2 answers
  • Most of an atom is empty space.
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!