Answer:
C. Waves transfer energy, but not matter.
Explanation: hope this helps :)
Answer C. 1.scientists learn by using the law of superposition B
When light travels from a medium with higher refractive index to a medium with lower refractive index, the critical angle is the angle of incidence above which light is reflected only (no refraction occurs), and the value of this critical angle is given by

where n2 is the refractive index of the second medium and n1 is the refractive index of the first medium.
In this problem, the first medium is the glass (

), while the second medium is oil (

), therefore the critical angle is given by
Answer:
1500N
Explanation:
Normal force = mg - F sin theta
constant velocity means acceleration = 0
F= ma = 150× 0 = 0N
thus;
normal force = mg = 150 × 10 = 1500N
A mirror equation is an equation that relates object distance and image distance to focal length. The distance of the image from the mirror will be -3 cm.
<h3>What is a mirror equation?</h3>
A mirror equation is an equation that relates object distance and image distance to focal length. It's sometimes referred to as a mirror formula.

The given data in the problem is;
f is the focal length = -4. 5 cm
u is the object distance=12. 0 cm
v is the image distance =?

Hence the distance of the image from the mirror will be -3 cm.
To learn more about the mirror equation refer to the link;
https://brainly.in/question/31545592