Answer:
v = 7.69 x 10³ m/s = 7690 m/s
T = 5500 s = 91.67 min = 1.53 h
Explanation:
In order for the satellite to orbit the earth, the force of gravitation on satellite must be equal to the centripetal force acting on it:

where,
G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²
Me = Mass of Earth = 5.97 x 10²⁴ kg
r = distance between the center of Earth and Satellite = Radius of Earth + Altitude = 6.371 x 10⁶ m + 0.361 x 10⁶ m = 6.732 x 10⁶ m
v = orbital speed = ?
Therefore,

<u>v = 7.69 x 10³ m/s</u>
For time period satellite completes one revolution around the earth. It means that the distance covered by satellite is equal to circumference of circle at the given altitude.
So, its orbital speed can be given as:

where,
T = Time Period of Satellite = ?
Therefore,

<u>T = 5500 s = 91.67 min = 1.53 h</u>
Answer:
Volume, V = 13564.8 cubic feet
Explanation:
It is given that,
Radius of the cylindrical tank, r = 12 feet
Height of the tank, h = 30 feet
We need to find the water that can be held by a cylindrical tank i.e. we need to find the volume of the tank. It is given by :


V = 13564.8 cubic feet
So, the water held by the tank is 13564.8 cubic feet. Hence, this is the required solution.