Answer:
The position on the x axis is 0.32 m.
Explanation:
Given that,
Point charge = 27 nC
Charge = 6 nC
Distance = 1
We need to calculate the distance
Using formula of electric field

Put the value into the formula






Hence, The position on the x axis is 0.32 m.
The Image distance and Magnification of The Image will be 30 cm and 3.
<h3>What is focal length?</h3>
The focal length of the lens, which is often expressed in millimeters, is the distance between the lens and the image sensor when the subject is in focus.
Given data;
Focal length,f=?
Image distance,v=?
Object distance,u= 10 cm
Magnification,m= 2.85
The focal length is half of the radius;
f=R/2
f=30 Cm/2
f= 15 Cm
The mirror equation is found as;

The magnification of the lens is found as;

Hence, the image distance and magnification of The image will be 30 cm and 3.
To learn more about the focal length refer;
brainly.com/question/16188698
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I think:
In motion- 40
Not moving- 20
Answer:

So a=3.844 and b=5
Explanation:
Scientific notation requests to write a number using powers of ten as a factor accompanying a real number (a) between 1 and smaller than 10 that contains the digits to exactly represent the original number. So in this case, the number 384,400 can be written as:

with a=3.844, and "5" as the exponent of ten (so b=5)