Answer:
New force, 
Explanation:
It is given that,
Force acting between two charged particles, 
We need to find the force if they are moved so they are only one-eighth as far apart.
The force between two charged particles separated at a distance of r is given by :
............(1)
If the charges are one-eighth as far apart then, r' =(1/8)r and new force is given by :
..........(2)
Dividing equation (1) and (2) :


F' = 48000 N
or

Hence, this is the required solution.
Given parameters:
Displacement = 8km
Velocity = 3.8km/h
Unknown:
time = ?
Solution:
Velocity is displacement divided by time.
Velocity =
Displacement = velocity x time
Input the parameters:
8 = 3.8 x time
Time =
= 2.1s
The time taken is 2.1s
Answer:
<em>Its speed will be 280 m/s</em>
Explanation:
<u>Constant Acceleration Motion</u>
It's a type of motion in which the speed of an object changes by an equal amount in every equal period of time.
If a is the constant acceleration, vo the initial speed, vf the final speed, and t the time, vf can be calculated as:

The object accelerates from rest (vo=0) at a constant acceleration of
. The final speed at t=35 seconds is:


Its speed will be 280 m/s
It will take 6.42 s for the ball that is dropped from a height of 206 m to reach the ground.
From the question given above, the following data were obtained:
Height (H) = 206 m
<h3>Time (t) =? </h3>
NOTE: Acceleration due to gravity (g) = 10 m/s²
The time taken for the ball to get to the ground can be obtained as follow:
H = ½gt²
206 = ½ × 10 × t²
206 = 5 × t²
Divide both side by 5

Take the square root of both side

<h3>t = 6.42 s</h3>
Therefore, it will take 6.42 s for the ball to get to the ground.
Learn more: brainly.com/question/24903556