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2 years ago

Calculate the pH of a buffer solution prepared by mixing 75.0 mL of 1.00 M lactic acid and 25.0 mL of 0.50 M sodium lactate.

Chemistry

1 answer:

max2010maxim [7]2 years ago

6 0

From the calculations, the pH of the buffer is 3.1.

<h3>What is the pH of the buffer solution?</h3>

The Henderson-Hasselbach equation comes in handy when we deal with the pH of a buffer solution. From that equation;

pH = pKa + log[(salt/acid]

Amount of the salt = 25/1000 * 0.50 M = 0.0125 moles

Amount of the acid = 75/1000 * 1.00 M = 0.075 moles

Total volume = ( 25 + 75)/1000 = 0.1 L

Molarity of salt = 0.0125 moles/0.1 L = 0.125 M

Molarity of the acid = 0.075 moles/0.1 L = 0.75 M

Given that the pKa of lactic acid is 3.86

pH = 3.86 + log( 0.125/0.75)

pH = 3.1

Learn more about pH:brainly.com/question/5102027

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snow_tiger [21]

Answer:

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Explanation:

Given parameters:

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Unknown:

Pressure exerted by her feet =?

Solution:

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Pressure = $\frac{force }{area}$

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3 years ago

Kc = 3.07 x 10-4 at 24°C for 2NOBr(g) ↔ 2NO(g) + Br2(g). If the initial concentration of NOBr = 0.878 M, what is the equilibrium

pav-90 [236]

Answer:

The equilibrium concentration of NO is 0.02124 M.

Explanation:

Given that,

Initial concentration of NOBr = 0.878 M

$k_{c}=3.07\times10^{-4}$

Temperature = 24°C

We know that,

The balance equation is

$2NOBr\Rightarrow 2NO+Br_{2}$

Initial concentration is,

$0.878\Rightarrow 0+0$

Concentration is,

$-2x\Rightarrow 2x+x$

Equilibrium concentration

$0.878-2x\Rightarrow 2x+x$

We need to calculate the value of x

Using formula of concentration

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Put the value into the formula

$3.07\times10^{-4}=\dfrac{[2x][x]}{[0.878-2x]^2}$

$2x^2=3.07\times10^{-4}\times(0.878)^2+3.07\times10^{-4}\times4x^2-2\times2x\times0.878\times3\times10^{-4}$

$2x^2=0.0002367+0.001228x^2-0.0010536x$

$2x^2-0.001228x^2+0.0010536x-0.0002367=0$

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Using formula of concentration of NO

$concentration\ of\ NO=2x$

Put the value of x

$concentration\ of\ NO=2\times0.01062$

$concentration\ of\ NO=0.02124$

Hence, The equilibrium concentration of NO is 0.02124 M.

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