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kotykmax [81]
2 years ago
6

What are some gases that dissolve in water?

Chemistry
2 answers:
maksim [4K]2 years ago
5 0

Explanation:

The main gases dissolved in purified water are oxygen and nitrogen, carbon dioxide, plus traces of inert gases, all in equilibrium with ambient air.

worty [1.4K]2 years ago
3 0

Answer:

The main gases dissolved in purified water are oxygen and nitrogen, carbon dioxide, plus traces of inert gases, all in equilibrium with ambient air.

Explanation:

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Ferrous ammonium sulfate is what kind of test method.
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Two things

Ferrous Ammonium Sulfate is a pale green or blue-green powder or sand-like solid. It is used in photography, analytical chemistry, and Iron-plating baths.

An FAS-DPD titration is as simple as a test for total alkalinity or calcium hardness. A buffered DPD indicator powder is added to a water sample and reacts with chlorine to produce the pink color characteristic of the standard DPD test.

Hope this it gang
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2 years ago
Which element would make a poor, brittle conductor? use the periodic table for help. a. sulfur b. boron c. cobalt d. calcium?
Greeley [361]
I think the answer is C or B
8 0
3 years ago
Classify each process as either physical or a chemical change.
Dafna11 [192]

Answer:

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7 0
3 years ago
A compound is 2.00% H by mass, 32.7% S by mass, and 65.3% O by mass. What is its empirical
Katarina [22]

Answer:

empirical formula: H_2SO_4

2 g H

32.7 g S

65.3 g O

Explanation:

Like the problem said, the first thing we can do is calculate the mass of each of the 3 elements in a 100-gram sample:

- 2.00% * 100g = 2 g H

- 32.7% * 100g = 32.7 g S

- 65.3% * 100g = 65.3 g O

Now we need to find the empirical formula from these. To do so, convert all of those masses into moles by using the molar mass for each element:

- the molar mass of H is 1.01 g/mol

- the molar mass of S is 32.06 g/mol

- the molar mass of O is 16 g/mol

2 g H ÷ 1.01 g/mol = 1.98 mol H

32.7 g S ÷ 32.06 g/mol = 1.02 mol S

65.3 g O ÷ 16 g/mol = 4.08 mol O

Our ratio of H : S : O is now:

1.98 mol : 1.02 mol : 4.08 mol

Divide them all by the smallest number, which is 1.02:

1.98/1.02  :  1.02/1.02  :  4.08/1.02

1.94 : 1 : 4

1.94 ≈ 2

So:

2 : 1 : 4

Thus, the empirical formula is: H_2SO_4.

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3 years ago
Q3.4. complex i transfers electrons to q (coenzyme q) in one of the reactions in the electron transport chain. which molecule is
xenn [34]
A small molecular in reaction to electron
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2 years ago
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