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serg [7]
2 years ago
10

How many particles are in a 151 g sample of Li2O?

Chemistry
1 answer:
neonofarm [45]2 years ago
4 0

Answer:

3.052 × 10^24 particles

Explanation:

To get the number of particles (nA) in a substance, we multiply the number of moles of the substance by Avogadro's number (6.02 × 10^23)

The mass of Li2O given in this question is as follows: 151grams.

To convert this mass value to moles, we use;

moles = mass/molar mass

Molar mass of Li2O = 6.9(2) + 16

= 13.8 + 16

= 29.8g/mol

Mole = 151/29.8g

mole = 5.07moles

number of particles (nA) of Li2O = 5.07 × 6.02 × 10^23

= 30.52 × 10^23

= 3.052 × 10^24 particles.

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Question 6 the chemical formula ch2o can be classified as: empirical only. molecular only. empirical, possibly molecular. not en
frosja888 [35]
The chemical formula CH2O can be classified as Empirical formula and possibly a molecular formula. The empirical formula of a compound is the simplest formula that indicates the simplest ratio of atoms in the compound, while the molecular formula is the representation of the actual whole number ratio between the elements of the compound. 
6 0
3 years ago
When 47.1 J of heat is added to 14.0 g of a liquid, its temperature rises by 1.80 ∘C. What is the heat capacity of the liquid?
Alja [10]

Answer:

\boxed {\boxed {\sf 1.87 \J/g \textdegree C}}

Explanation:

We are asked to find the specific heat capacity of a liquid. We are given the heat added, the mass, and the change in temperature, so we will use the following formula.

q= mc\Delta T

The heat added (q) is 47.1 Joules. The mass (m) of the liquid is 14.0 grams. The specific heat (c) is unknown. The change in temperature (ΔT) is 1.80 °C.

  • q= 47.1 J
  • m= 14.0 g
  • ΔT= 1.80 °C

Substitute these values into the formula.

47.1 \ J = (14.0 \ g) * c * (1.80 \textdegree C)

Multiply the 2 numbers in parentheses on the right side of the equation.

47.1 \ J = (14.0 \ g * 1.80 \textdegree C)*c

47.1 \ J = (25.2 \ g*\textdegree C) *c

We are solving for the heat capacity of the liquid, so we must isolate the variable c. It is being multiplied by 25.2 grams * degrees Celsius. The inverse operation of multiplication is division, so we divide both sides of the equation by (25.2 g * °C).

\frac {47.1 \ J}{(25.2 g *\textdegree C)} = \frac {(25.2 g *\textdegree C)*c}{{(25.2 g *\textdegree C)}}

\frac {47.1 \ J}{(25.2 g *\textdegree C)} =c

1.869047619 \ J/g *\textdegree C = c

The original measurements of heat, mass, and temperature all have 3 significant figures, so our answer must have the same. For the number we found that is the hundredth place. The 9 in the thousandth place to the right tells us to round the 6 up to a 7.

1.87 \ J/ g * \textdegree C =c

The heat capacity of the liquid is approximately 1.87 J/g°C.

3 0
3 years ago
Assume you find four bottles in an empty laboratory, each containing a liquid. The labels that were on these bottles have fallen
fenix001 [56]

Answer:

No, I can not identify the contents of each bottle using solubility and polarity (with H2O) information

Explanation:

While it is true that polar substances dissolve in water and nonpolar substances do not dissolve in water, the task here is to specifically identify the contents of each of the bottles.

Solubility in water can not tell us exactly what liquid is which substance. For instance, trans-1,2-dichloroethylene, cis-1,2-dichloroethylene and cyclooctane are all insoluble in water. The fact that they do not dissolve in water does not tell us which liquid is which compound.

Even though acetic acid is miscible with water, it is not a conclusive prove that the liquid is acetic acid since other polar organic compounds are also miscible in water.

It is only by determining the boiling point of each substance that I can conclusively identify the contents of each bottle since boiling point is an intrinsic property of substances.

6 0
2 years ago
Gasoline has a density of 0.749 g/ml. how many pounds does 19.2 gallons of gasoline weigh?
Svetradugi [14.3K]
A good first step is writing the amount in terms of ml. 

19.2 gallons = 72.68 L = 72680 ml

that would mean it weighs 0.749*720680g = 54437.32ml = 54.437 L

hope that helps :)
6 0
2 years ago
Read 2 more answers
Which of the following reactions does the coenzyme biotin catalyze?
Papessa [141]

Answer:

c. decarboxylation of an a-keto acid.

Explanation:

Decarboxylation refers to the removal of the carboxyl group from a carboxylic acid and thus releasing carbon dioxide. Decarboxylases are enzymes that speed up the removal of the carboxyl group from acids. These reactants could be amino acids, alpha-keto acids, and beta-keto acids. Biotin is known to catalyze the decarboxylation of malonyl CoA to acetyl CoA during fatty acid synthesis.

Malonyl CoA is converted to acetyl CoA after decarboxylation assisted by biotin also known as Vitamin H. Alpha keto acids are involved in fatty acids synthesis and Malonyl CoA is an alpha-keto acid because the keto group is located in the first carbon near the carboxylic acid group. Keto acids have both a carboxyl group and a ketone group.

5 0
2 years ago
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