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SCORPION-xisa [38]
1 year ago
7

Use a periodic table to help you answer these questions if needed.

Chemistry
1 answer:
yuradex [85]1 year ago
3 0

Answer:

2 Al and 3 S

Explanation:

Al2S3 so 2 Al and 3 S

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Write a net ionic equation for the overall reaction that occurs when aqueous solutions of sodium hydroxide and hydrosulfuric aci
Helga [31]

Answer:

2OH-(aq) + 2H+(aq) → 2H2O(l)

Explanation:

Step 1: Data given

sodium hydroxide = NaOH

hydrosulfuric acid = H2S

Step 2: The unbalanced equation

NaOH(aq) + H2S(aq) → Na2S(aq) + H2O(l)

Step 3: Balancing the equation

On the left side we have 1x Na (in NaOH), on the right side we have 2x Na (in Na2S). To balance the amount of Na on both sides, we have to multiply NaOH on the left side by 2.

2NaOH(aq) + H2S(aq) → Na2S(aq) + H2O(l)

On the left side we have 4x H (2x in NaOH and 2x in H2S), on the right side we have 2x H (in H2O). To balance the amount of H on both sides, we have to multiply H2O on the right side by 2. Now the equation is balanced.

2NaOH(aq) + H2S(aq) → Na2S(aq) + 2H2O(l)

Step 4: The net ionic equation

2Na+(aq) + 2OH-(aq) + 2H+(aq) + S^2-(aq) → 2Na+(aq) + S^2-(aq) + 2H2O(l)

The net ionic equation, for which spectator ions are omitted - remember that spectator ions are those ions located on both sides of the equation - will , after canceling those spectator ions in both side, look like this:

2OH-(aq) + 2H+(aq) → 2H2O(l)

8 0
3 years ago
Which compound is an Arrhenius base?(1) CH3OH (3) LiOH<br> (2) CO2 (4) NO2
nydimaria [60]
Lithium Hydroxide (LiOH) is an Arrhenius base
7 0
3 years ago
Read 2 more answers
How to know how many valence electrons are in an element
Alenkinab [10]

Answer:

Hope it helped

Explanation:

For neutral atoms, the number of valence electrons is equal to the atom's main group number. The main group number for an element can be found from its column on the periodic table. For example, carbon is in group 4 and has 4 valence electrons. Oxygen is in group 6 and has 6 valence electrons.

7 0
3 years ago
The mass of an erlenmeyer flask is 85.135 g. after 10.00 ml of water is added to the flask, the mass of the flask and the water
BARSIC [14]
Subtracting the mass of (flask+water) from the empty flask gives:
95.023 g - 85.135 g = 9.888 grams of water
Dividing this by the given volume of 10.00 mL water gives:
9.888 grams of water / 10.00 mL of water = 0.9888 g/mL of water
Therefore, based on this sample, the density of water is 0.9888 g/mL, which is close to the usually accepted approximation of 1 g/mL.
4 0
3 years ago
Consider the following gas samples: 10. g of hydrogen gas, 10. g of helium gas, 2.5 moles of nitrogen gas, 110. g of carbon diox
Pepsi [2]

Explanation:

As we know ,

One mole of a gas contains 6.023 * 10 ²³ number of atoms .

Moles is denoted by given mass divided by the molecular mass ,  

Hence ,  

n = w / m

n = moles ,  

w = given mass ,  

m = molecular mass .

( a ) From the question ,

w = 10 g ,

As we know molecular mass of Hydrogen = 2 g/mol

Using the above formula , and putting the respective values ,

Moles = n ,

n = w / m  = 10 / 2 = 5 mol

The number of atoms in one molecule of Hydrogen = 2

Hence ,

The number of atoms = 5 * 2 *  6.023 * 10 ²³ = 60.23 * 10 ²³ atoms .

( b )  From the question ,

w = 10 g

As we know molecular mass of helium gas = 4 g/mol

Using the above formula , and putting the respective values ,

Moles = n ,

n = w / m  = 10 /4 = 2.5 mol

The number of atoms in one molecule of Helium = 1

Hence ,

The number of atoms = 5 * 1 *  6.023 * 10 ²³ = 30.115 * 10 ²³ atoms .

( c ) From the question ,

moles of nitrogen gas = 2.5 mol

The number of atoms in one molecule of  nitrogen gas = 2

Hence ,

The number of atoms = 2.5 * 2 *  6.023 * 10 ²³ = 30.115 * 10 ²³ atoms .

( d ) From the question ,

w = 110 g

As we know molecular mass of carbon dioxide gas = 44 g/mol

Using the above formula , and putting the respective values ,

Moles = n ,

n = w / m  = 110 / 44 = 2.5 mol

The number of atoms in one molecule of  carbon dioxide = 3

Hence ,

The number of atoms = 2.5 * 3 *  6.023 * 10 ²³ = 45.17 * 10 ²³ atoms .

( e )

From the question ,

w = 365 g

As we know molecular mass of  sulfur hexafluoride gas = 146 g/mol

Using the above formula , and putting the respective values ,

Moles = n ,

n = w / m  =  365 / 146 = 2.5 mol .

The number of atoms in one molecule of sulfur hexafluoride gas = 7

Hence ,

The number of atoms = 2.5 * 7 *  6.023 * 10 ²³ = 105.40 * 10 ²³ atoms .

Hence ,

The order is -

sulfur hexafluoride > Hydrogen > carbon dioxide  > nitrogen gas = helium gas

4 0
3 years ago
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