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3 years ago

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What is a cause of cemical weathering? A. sunlight B. wind C. gravity D. acids

2 answers:

siniylev [52]3 years ago

4 0

D. Acids I hope this helped ur welcome

Taya2010 [7]3 years ago

4 0

Answer:

D. acids

Explanation:

I hope this helped

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What is the mass in grams of 9.76 x 10 12 atoms of naturally occurring sodium?

Fiesta28 [93]

The number of moles in a substance indicates the amount of the substance that contains the same number of particles as 12 g of the Carbon-12 isotope [or equivalent to 6.02 × 10²³] (which is used as a standard in the world of moles).

Now,

if 6.02 × 10²³ atoms are found in 1 mole ofsodium
then let 9.76 × 10¹² atoms are found in x

⇒ x = (9.76 × 10¹² ) ÷ (6.02 × 10²³)

= 1.619 × 10⁻¹¹ mol

Now, mass = moles × molar mass

∴ mass of Na = 1.619 × 10⁻¹¹ mol × 23 g/mol
= 3.72 × 10⁻¹⁰ g

4 0

3 years ago

The Ostwald process for the commercial production of nitric acid from ammonia and oxygen involves the following steps:

bagirrra123 [75]

Answer:

$12 NH_3 (g)+ 21 O_2 (g) + \longrightarrow 14 H_2O (l) + 8 HNO_3 (g) + 4 NO (g)$

Explanation:

The steps of the Ostwald process:

$4 NH_3 (g) + 5 O_2 (g) \longrightarrow 4 NO (g) + 6 H_2O (g)$

$2 NO (g) + O_2 (g) \longrightarrow 2 NO_2 (g)$

$3 NO_2 (g) + H_2O (l) \longrightarrow 2 HNO_3 (g) + NO (g)$

Combinning the equations:

$4 NH_3 (g) + 5 O_2 (g) \longrightarrow 4 NO (g) + 6 H_2O (g)$

+

$(2 NO (g) + O_2 (g) \longrightarrow 2 NO_2 (g))*2$

+

$(3 NO_2 (g) + H_2O (l) \longrightarrow 2 HNO_3 (g) + NO (g))*4/3$

=

$4 NH_3 (g)+ 4 NO (g)+ 7 O_2 (g) + 4 NO_2 (g) +4/3 H_2O (l) \longrightarrow 4 NO (g) + 6 H_2O (g) + 4 NO_2(g) + 8/3 HNO_3 (g) + 4/3 NO (g)$

Simplifying:

$4 NH_3 (g)+ 7 O_2 (g) + \longrightarrow 14/3 H_2O (l) + 8/3 HNO_3 (g) + 4/3 NO (g)$

$12 NH_3 (g)+ 21 O_2 (g) + \longrightarrow 14 H_2O (l) + 8 HNO_3 (g) + 4 NO (g)$

The overall reaction is endothermic becuase the formation of new chemical bonds requires energy consumption.

4 0

3 years ago

How many moles of NaCl are present in 2.50 L of a 0.070 M solution?

posledela

Given :

Volume of NaCl solution 2.5 L .

Molarity of NaCl solution is 0.070 M .

To Find :

How many moles are present in the solution.

Solution :

Let, n be the number of moles.

We know, molarity is given by :

$M = \dfrac{n}{V(in\ L)}$

So,

$n = M \times V\\\\n = 0.070\times 2.5 \\\\n = 0.175\ moles$

Therefore, number of moles of NaCl is 0.175 moles.

6 0

3 years ago

HHHAAAAALLLPPPP<br><br> It’s due tomorrow

iris [78.8K]

Answer:

D.

Explanation:

Only 0.0035% of the electromagnetic spectrum is visible to the human eye

Hopefully this helped :)

7 0

3 years ago

Can someone tell me how to solve this step by step? I got the answer but I want to know how to solve it I have a test !!!!

UNO [17]

C becuase that is the one that you would have to do becuase that is the only option

6 0

3 years ago