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Alex Ar [27]
3 years ago
11

How many moles of lithium metal would need to react with excess oxygen gas to produce 4 moles of lithium oxide in the following

reaction? 4Li + O2 → 2Li2O
Chemistry
1 answer:
irina1246 [14]3 years ago
3 0

8 moles of Lithium are needed.

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Is trimming a bush because it grows too tall a chemical or physical change
professor190 [17]

Answer:

Physical Change

Explanation:

The bush is changing shapes, not changing what it is.

8 0
3 years ago
A 20.00 ml sample of a solution of sr(oh)2 is titrated to the equivalence point with 40.03 ml of 0.1159 n hcl. what is the molar
goblinko [34]
The   molarity  of Sr(OH)2  solution is  =  0.1159 M

    calculation
write the equation  for reaction
that is,  Sr(OH)2 +2HCl→ SrCl2 + 2 H2O

then finds the mole  of HCl used

moles = molarity x volume 
=40.03 x0.1159 =  4.639 moles

by  use of mole ratio between Sr(OH)2 to  HCL which is 1 :2  the moles of Sr(OH)2  is therefore =  4.639  x1/2 = 2.312  moles

molarity  of  Sr(OH)2  is =  moles  / volume

=2.312 /20 =0.1159 M
3 0
3 years ago
A liquid has a _____.
guajiro [1.7K]

Answer:

definite volume

Explanation:

hope this helps!❆

3 0
2 years ago
Read 2 more answers
PLEASE HELP ME WITH THIS ONE QUESTION!!
Ksenya-84 [330]
2 I think not 100% tho
5 0
3 years ago
What is the empirical formula for the following molecular formula: C10H5O2
Tju [1.3M]

The empirical formula is the same as the molecular formula : C₁₀H₅O₂

<h3>Further explanation</h3>

Given

Molecular formula : C₁₀H₅O₂

Required

The empirical formula

Solution

The empirical formula (EF) is the smallest comparison of atoms of compound forming elements.  

The molecular formula (MF) is a formula that shows the number of atomic elements that make up a compound.  

(empirical formula) n = molecular formula  

<em>(EF)n=MF </em>

(EF)n = C₁₀H₅O₂

If we divide by the number of moles of Oxygen (the smallest) which is 2 then the moles of Hydrogen will be a decimal number (not whole), which is 2.5, then the empirical formula is the same as the molecular formula

4 0
3 years ago
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