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andrew11 [14]
2 years ago
6

WILL GIVE BRAINLIEST

Mathematics
1 answer:
Alja [10]2 years ago
8 0

A. The pair of linear equations are: x + y = 55 and y = x + 25

B. Number of time she spend running everyday is: 15 minutes.

C. It is not possible.

<h3>How to Write a System of Linear Equations?</h3>

A system of equations consist of linear equations that have unknown variables whose values make the linear equations in the system true.

<u>Part A:</u> To write a pair of linear equations, do the following,

Let x represent the time Jackie runs

Let y represent the time Jackie dances

We are given that, Jackie runs and dances for a total of 55 minutes every day, therefore, the first linear equation would be:

x + y = 55 --> equation 1

We are also given that Jackie dances for 25 minutes longer than she runs, therefore, the second linear equation would be:

y = x + 25 --> equation 2

Therefore, the two pair of linear equations that shows the relationship between the number of minutes Jackie runs and dances everyday are:

x + y = 55

y = x + 25

Part B: Substitute y = (x + 25) into equation 1

x + y = 55 --> equation 1

x + x + 25 = 55

2x + 25 = 55

2x = 55 - 25

2x = 30

x = 15

Therefore, the number of time she spend running everyday is: 15 minutes.

Part C:

If she spent 45 minutes dancing (y = 45), and x = 15, substitute the values into x + y = 55 to find out if it is possible.

15 + 45 = 55

60 = 55 (not true)

Therefore, it is not possible.

Learn more about the system of equations on:

brainly.com/question/13729904

#SPJ1

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Answer:

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Step-by-step explanation:

The preimeter is adding all sides together. I took 154-55 twice sense we have four sides of a rectangle and two are lengths. after that i got 44. I then just remembered we had two sides left so divided that by 2 and got 22

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Step-by-step explanation:

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Read 2 more answers
Evaluate the function at the indicated values if possible. If an indicated value is not in the​ domain, say so.
goldfiish [28.3K]

Answer:

f(-7)=0.

f(2)=-9/5.

f(3) doesn't exist because 3 isn't in the domain of the function.

Step-by-step explanation:

f(x)=\frac{x+7}{x^2-9} is the given function.

We are asked to find:

f(-7)

f(2)

f(3).

f(-7) means to replace x in the expression called f with -7:

Evaluate \frac{x+7}{x^2-9} at x=-7

\frac{(-7)+7}{(-7)^2-9}

\frac{0}{49-9}

\frac{0}{40}

0

So f(-7)=0.

f(2) means to replace x in the expression called f with 2:

Evaluate \frac{x+7}{x^2-9} at x=2

\frac{2+7}{2^2-9}

\frac{9}{4-9}

\frac{9}{-5}

\frac{-9}{5}

So f(2)=-9/5

f(3) means to replace x in the expression called f with 3:

Evaluate \frac{x+7}{x^2-9} at x=3

\frac{3+7}{3^2-9}

\frac{10}{9-9}

\frac{10}{0}

Division by 0 is not allowed so 3 is not in the domain of our function.

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3 years ago
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