Answer:
1 is 8x + 16 = 6x
Step-by-step explanation:
The Answer is a b¹⁰
Simplify the following:
(a^5 b^6 b^4)/a^4
Combine powers. (a^5 b^6 b^4)/a^4 = a^(5 - 4) b^(6 + 4):
a^(5 - 4) b^(6 + 4)
5 - 4 = 1:
a b^(6 + 4)
6 + 4 = 10:
Answer: a b^10
We are given with two equations 2x − 3y = −1 and <span>11x − 9y = −13. The problem says that when the first equation is multiplied by -3 which results to -6x + 9y = 3, the sum of the resulting equation and the second one is equal to 5x = -10. We verify this: -6x + 11x = 5x while -9 y and 9 y cancels out. 3+-13 equals -10. Hence the total is really 5x = - 10.</span>
Always.
So it is B.
Hope This Helps
Presuming the question is "Which sum is closest to 1".
First, you need to either convert all the fractions to decimals or all the decimals to fractions, then add each pair.
0.4 + 1/2 = 0.9
7/8 + 1/4 = 1.125
4/5 + 2/3 = 1.466666...
The first one is different from 1 by 0.1. The second is different by 0.125. The third is different by 0.46666.... Therefore, the closest sum is the first, or 0.4 + 1/2
0.4 + 1/2
