hey,
I'm here to help
just multiply each mouse's velocity components
then,
add them all up to get x,y total
Answer:
A) P1=2 [bar] , W=-12 [kJ]
B) P1=0.8 [bar] , W=-7.3303 [kJ]
C) P1=0.6077 [bar] , W=-6.4091 [kJ]
Explanation:
First, from the problem we know the following information:
V1=0.1 m^3
V2=0.04 m^3
P2=2 bar =200 kPa
The relation PV^n=constant means PV^n is a constant through all the process, so we can derive the initial pressure as:
a) To the case a) the constant n is equal to 0, we can calculate the initial pressure substituting n=0 in the previous expression, so:
The expression to calculate the work is:
If n=0:
Then:
The work is:
b) To the case b) the constant n is equal to 1, we can calculate the initial pressure substituting n=1 in the initial expression, so:
If n=1 then:
To calculate the work:
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Substituting:
c) To the case c) the constant n is equal to 1.3, we can calculate the initial pressure substituting n=1.3 in the initial expression, so:
First:
The work:
Substituting:
W=-6.4091 kJ
B. Static friction force - static friction is the force put on an object to keep that same object at rest
Answer:
the spring coefficient is
k=16N/m
Explanation:
Hooks law states that provided the elasticity of a material is not exceeded the extension e is proportional to the applied force
Step one
Analysis of the problem
From analysis of the problem
The mass has a potential energy due to the height it was dropped from, the potential energy is then stored in the spring since it was dropped on the spring which compresses it by 0.5m
Step two
Data
Mass of object m=0.2kg
Height of building =10m
Compression of spring e=0.5m
Spring constant k=?
Step three
According to the principle of energy conservation
mgh=1/2(k*e^2)
Making k subject of formula we have
k=2mgh/e^2
Substituting our data into the expression to get k
Assuming g=9.81m/s
k=2*0.2*10/0.5^2
k=4/0.25
k=16N/m