Question

Monochromatic light with wavelength 590 nm passes through a single slit 2. 30 ?m wide and 1. 90 m from a screen. Find the distance between the first- and second-order dark fringes on the screen.

Answer 1

Answer:

The fringes are 4.7*10^-7 m apart, such that they are adjacent.

Explanation:

Using the formula for adjacent fringes given a single slit:

Δ$x=\frac{(Wavelength)(Distance between slit and screen)}{Width}$

Δ$x=\frac{(590/10^{9})(1.90) }{(2.30)}$

Δ$x=0.000000487 m$

Hope this helps!

Answer 2

The distance between the first-order and second-order dark fringes on the screen will be 4.874 × 10⁻⁵ cm.

Given:

wavelength, λ = 590 nm = 590 × 10⁻⁹ m

Distance between the slit and screen, D = 1.90 m

Width of slit, d = 2.30 m

Calculation:

We know that the distance between two slits is given as:

Δx = λD / d

where  λ is the wavelength of light

           D is the distance between the slit and screen

           d is the width of the slit

Applying values in the above equation we get:

Δx = (590 × 10⁻⁹ m)(1.90 m) / (2.30 m)

    = 4.874 × 10⁻⁷ m

    = 4.874 × 10⁻⁵ cm

Therefore, the distance between the first- and second-order dark fringes on the screen will be 4.874 × 10⁻⁵ cm.

Learn more about interference here:

brainly.com/question/16098226

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