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Luda [366]
2 years ago
13

Match each term with its definition.

Physics
1 answer:
Neporo4naja [7]2 years ago
6 0

The correct matches are as follows:

  • malleability - the ability of metals to be shaped by hammering or pounding
  • metallic bond - the bond formed when metal atoms share many mobile electrons
  • alloy - a mixture of the atoms of a metal with another element
  • ductility - the ability of metals to be formed into wires
  • electron sea theory - metals bond to other metals by sharing many "floating electrons

<h3>What are metals?</h3>

Metals are elements which form positive ions by loss of electrons.

Metals are usually shiny, malleable and ductile.

Metal atoms combine are bonded to each other by metallic bonds.

Electron sea theory describe how mobile electrons  surround positive atomic nucleus.

Alloys refer to a mixture of metals.

In conclusion, metal atoms form metallic bonds.

Learn more about metals at: brainly.com/question/4701542

#SPJ1

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It takes you 9.8 min to walk with an average velocity of 1.9 m/s to the north from the bus stop to the museum entrance.
Dahasolnce [82]
60 x 9.8 = 588
588 x 1.9 = 1117.2
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Why does the sun move across the sky
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3 years ago
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Why isn't the earth the same distance from sun all year long?
miskamm [114]

Answer:

Earth's orbit is elliptical

Explanation:

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How do i solve the ones in red? A student fires a cannonball horizontally with a speed of 24.0m/s from a height of 51.0m. Neglec
Rus_ich [418]

Horizontal speed = 24.0 m/s

height of the cliff = 51.0 m

For the initial vertical speed will are considering the vertical component. Therefore,

Since the student fires the canonical ball at the maximum height of 51 m, the initial vertical velocity will be zero. This means

\text{ Initial vertical velocity = 0 m/s}

let's find how long the ball remained in the air.

\begin{gathered} 0=51-\frac{1}{2}(9.8)t^2 \\ 4.9t^2=51 \\ t^2=\frac{51}{4.9} \\ t^2=10.4081632653 \\ t=\sqrt[]{10.4081632653} \\ t=3.22 \\ t=3.22\text{ s} \end{gathered}

Finally, let's find the how far from the base of the building the ball landed(horizontal distance)

\begin{gathered} S_x=u_xt+\frac{1}{2}a_xt^2 \\ S_x=24\times3.23 \\ S_x=\text{horizontal distance=77.28 m} \\ \text{note} \\ a_x=0m/s^2 \end{gathered}

6 0
2 years ago
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