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Dafna11 [192]
3 years ago
15

Two balls, each with a mass of 0.890 kg, exert a gravitational force of 8.06 × 10−11 n on each other. how far apart are the ball

s? the value of the universal gravitational constant is 6.673 × 10−11 n m2 /kg2 . answer in units of m.
Physics
1 answer:
Bond [772]3 years ago
6 0
This problem involves Newton's universal law of gravitation and the equation to follow would be.

F = GM₁M₂/r²  

Given: M₁ = 0.890 Kg;  M₂ = 0.890 Kg;  F = 8.06 x 10⁻¹¹ N; G = 6.673 X 10⁻¹¹ N m²/Kg²

Solving for distance r = ?

r = √GM₁M₂/F

r = √(6.673 x 10⁻¹¹ N m₂/Kg²)(0.890 Kg)(0.890 Kg)/ 8.06 x 10⁻¹¹ N

r = 0.81 m 
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7.
Igoryamba

D. Free fall

Explanation:

An object is said to be in free fall when there is only one force acting on the body, which is the force of gravity.

Near the Earth's surface, the force of gravity acting on a body is given by

F = mg

where

m is the mass of the body

g is the acceleration of gravity (its value is 9.8 m/s^2)

The direction of this force is downward (towards the Earth's centre).

If we apply Newton's second law on an object in free-fall, we can find its acceleration. In fact, we have:

a=\frac{F}{m}

And substituting F,

a=\frac{mg}{m}=g=9.8 m/s^2

So, every object in free-fall accelerates at 9.8 m/s^2 towards the ground.

Learn more about free fall here:

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5 0
3 years ago
Read 2 more answers
A car is traveling at a speed of 38.0 m/s on an interstate highway where the speed limit is 75.0 mi/h. Is the driver exceeding t
lidiya [134]

Answer:

Yes, the car driver is exceeding the given limit.

Explanation:

<u>Given:</u>

  • Speed of the car, v = 38.0 m/s.
  • Speed limit of the highway, \rm v_o=75.0\ mi/h.

<h2><u>Converting the speed limit from mi/h to m/s:</u></h2>

We know,

1 mi = 1.60934 km.

1 km = 1000 m.

Therefore, 1 mi = 1.60934 × 1000 m = 1609.34 m.

1 hour = 60 minutes.

1 minute = 60 seconds.

Therefore, 1 hour = 60 × 60 seconds = 3600 seconds.

Using these values,

\rm 1\ \dfrac{mi}{h}=\dfrac{1609.34\ m}{3600\ s}=0.447\ m/s.

Therefore,

\rm v_o = 75.0\ mi/h=75.0\times 0.447=33.52\ m/s.

Clearly,

\rm v_o

which means, the car driver is exceeding the given speed limit.

6 0
3 years ago
is the science that manages the database, digital tools, and software used by both medicine and forensic science to store and an
Ne4ueva [31]

Explanation :

Bioinformatics is the science that manages the database, digital tools and software used by both medicine and forensic science to store and analyze DNA.

It involves the use of computers to collect all the data and organize data. It also develops methods and computational tools for understanding biological data.

It helps in tracing the evolution of organism using DNA and builds a computational model.

8 0
3 years ago
Why are there temperature differences on the moon's surface even though there is no atmosphere present?
nika2105 [10]

The lack of an atmosphere means convection cannot happen on the moon. Therefore, there is no form of heat dissipation on regions in direct sunlight. In addition, the lack of an atmosphere means there is no greenhouse effect on the moon. This is why regions facing away from sunlight are very cold.  

4 0
3 years ago
What is the net work doneon the object over the distance shown?
GuDViN [60]

A)F_0d

Explanation

If you graph the force on an object as a function of the position of that object, then the area under the curve will equal the work done on that object, so we need to find the area under the function to find the work

Step 1

find the area under the function.

so

Area:

\text{Area}=rec\tan gle_{green}+triangle_{gren}-triangle_{red}\begin{gathered} \text{the area of a rectangle is given by} \\ A_{rec}=lenght\cdot widht \\ \text{and} \\ \text{the area of a triangle is given by:} \\ A_{tr}=\frac{base\cdot height}{2} \end{gathered}

so

\begin{gathered} \text{Area}=rec\tan gle_{green}+triangle_{gren}-triangle_{red} \\ \text{replace} \\ \text{Area}=(F_0\cdot d)+\frac{(F_0\cdot d)}{2}-\frac{(F_0\cdot d)}{2} \\ \text{Area}=(F_0\cdot d) \\ Area=F_0d \end{gathered}

therefore, the answer is

A)F_0d

I hope this helps you

4 0
1 year ago
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