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puteri [66]
3 years ago
14

A cart is pushed on a frictionless floor with 29.6 Newtons of force along a distance of 5.9 meters in 8.1 seconds. How much powe

r is exerted
during this time period?
Physics
1 answer:
marta [7]3 years ago
8 0

Answer:

Power = 21.6 Watts

Explanation:

Power = \frac{W}{t}

Where W = work and t = time.

W = Fs

Where F is force and s is displacement.

29.6N(5.9m) = 174.64J

W = 174.64J

Power = \frac{174.64J}{8.1s}

Power = 21.6 Watts

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A ball that rolls on the ground is initially propelled with a speed of 45 km / h and after 10 seconds it stops. Assuming you los
solmaris [256]

Answer:

a) -1.25 m/s²

b) 62.5 m

Explanation:

Convert km/h to m/s:

45 km/h × (1000 m/km) × (1 h / 3600 s) = 12.5 m/s

a = Δv / Δt

a = (0 m/s − 12.5 m/s) / 10 s

a = -1.25 m/s²

Δx = ½ (v + v₀) t

Δx = ½ (0 m/s + 12.5 m/s) (10 s)

Δx = 62.5 m

5 0
3 years ago
How much energy is needed to melt 150 g of ice at 0°C to water? (1)(Lf =3.34˟ 10⁵ J/Kg)
NARA [144]

Answer:

5.01×10⁴ J.

Explanation:

Applying,

q = Cm....................... Equation 1

Where q = amount of heat needed to melt the ice, m = mass of the ice, C = specific latent heat of ice.

From the question,

Given: m = 150 g = (150/1000) kg = 0.15 kg, C = 3.34×10⁵ J/kg

Substitute these values into equation 1

q = (0.15×3.34×10⁵)

q = 0.501×10⁵ J

q = 5.01×10⁴ J.

5 0
3 years ago
Hi, I was wondering why do in real life we refer our weight as for example 54kg instead of 540N? When we know that weight is a f
Kazeer [188]

Answer:

Chicken nuggets

Explanation:

Because

8 0
3 years ago
How does muscle fatigue affect the amount of work that muscles can do?
Ganezh [65]

Answer:

by straining that muscle it can slow down the amount of muscle your supposed to get

Explanation:

6 0
3 years ago
Read 2 more answers
What current flow (I) is associated with an input voltage of 5.0V and resistors R1 = 1.5 kiloohms and R2 = 0.5 kiloohms? Calcula
Y_Kistochka [10]

Answer:

current in series is 2.50 mA

current in parallel is 13.51 mA

Explanation:

given data

voltage = 5 V

resistors R1 = 1.5 kilo ohms

resistors R2 = 0.5 kilo ohms

to given data

current flow

solution

current flow in series is express as here

current = voltage / resistor    .................1

put here all value  in equation 1

current = 5 / (1.5 + 0.5)

current = 5 / 2.0

so current = 2.50 mA

and

current flow in parallel is express as

current = voltage / resistor   ....................2

put here all value in equation  2

current = 5 / (1/ (1/1.5 + 1/0.5))

current = 5 / 0.37

so current = 13.31 mA

5 0
3 years ago
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