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2 years ago

11

What is kinematics ?explain ~

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tysm! :)

2 answers:

SpyIntel [72]2 years ago

7 0

Answer:

the branch of mechanics concerned with the motion of objects without reference to the forces which cause the motion is kinematics

VladimirAG [237]2 years ago

3 0

Answer:

Kinematics is the study of the motion of mechanical points, bodies and systems without consideration of their associated physical properties and the forces acting on them. The study is often referred to as the geometry of motion, and it models these motions mathematically using algebra

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Explanation:

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3 years ago

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Students are completing a lab in which they let a lab cart roll down a ramp. The students record the mass of the cart, the heigh

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3 years ago

An ideal gas, initially at a pressure of 11.2 atm and a temperature of 299 K, is allowed to expand adiabatically until its volum

Tju [1.3M]

Answer:

The pressure is $P_2 = 4.25 \ a.t.m$

Explanation:

From the question we are told that

The initial pressure is $P_1 = 11.2\ a.t.m$

The temperature is $T_1 = 299 \ K$

Let the first volume be $V_1$ Then the final volume will be $2 V_1$

Generally for a diatomic gas

$P_1 V_1 ^r = P_2 V_2 ^r$

Here r is the radius of the molecules which is mathematically represented as

$r = \frac{C_p}{C_v}$

Where $C_p \ and\ C_v$ are the molar specific heat of a gas at constant pressure and the molar specific heat of a gas at constant volume with values

$C_p=7 \ and\ C_v=5$

=> $r = \frac{7}{5}$

=> $11.2*( V_1 ^{\frac{7}{5} } ) = P_2 * (2 V_1 ^{\frac{7}{5} } )$

=> $P_2 = [\frac{1}{2} ]^{\frac{7}{5} } * 11.2$

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3 years ago

A student sits on a rotating stool holding two 2.8-kg objects. When his arms are extended horizontally, the objects are 1.0 m fr

Sindrei [870]

Answer:

Explanation:

Given

mass of objects m is 2.8 kg

objects is $r=1 m$ away from axis of rotation

angular velocity $\omega _1=0.75 rad/s$

moment of inertia of stool and student is $=3 kg-m^2$

New distance of objects $r'=0.34 m$

conserving Angular momentum

Initial Angular momentum $L_1=I\omega _1$

$I_1=3+2\times 2.8\times 1^2$

$I_1=3+5.6=8.6 kg-m^2$

$L_1=8.6\times 0.75=6.45$

For Second case

$I_2=3+2\times 2.8\times 0.34^2=3.32 kg-m^2$

$L_2=3.32\times \omega _2$

$L_1=L_2$

$6.45=3.32\times \omega _2$

$\omega _2=1.94 rad/s$

5 0

3 years ago