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nasty-shy [4]
3 years ago
6

What is the net force of an object travelling at a constant velocity of 50 miles per hour south?? Question 4 options: 25 N 0 N 5

0 N 100 N
Physics
2 answers:
Darina [25.2K]3 years ago
7 0
The answer is 0 N because for something to have a constant velocity, all of it’s forces must add up to zero.
LiRa [457]3 years ago
4 0
The correct answer is 0 n    For<span> instance, if the wheels of a car push it forward with 5 Newtons and drag is 3 ... An unbalanced force (</span>net force<span>) acting on an </span>object<span> changes its speed and/or direction of motion. ... is no </span>net force, theobject<span> will not accelerate and the </span>velocity<span> will remain </span>constant<span>. ... Let's assume that the wheels of a car apply 10 </span>N<span> of force.  Hope I helped God bless you and your family your in my prayers Free Tay K</span>
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A 4.8-kg block attached to a spring executes simple harmonic motion on a frictionless horizontal surface. At time t=0 s, the blo
garri49 [273]

Answer:

E) 80 N/m

Explanation:

Given;

mass of the block, m = 4.8 kg

displacement of the block, x = -0.5 m

velocity of the block, v = -0.8 m/s

acceleration of the block, a = 8.3 m/s²

From Newton's second law of motion;

F = ma

Also, from Hook's law;

F = -Kx

where;

k is the force constant

Thus, ma = -kx

k = -ma/x

k = -(4.8 x 8.3) / (-0.5)

k = 79.7 N/m

k ≅ 80 N/m

Therefore, the force constant of the spring is closest to 80 N/m

4 0
3 years ago
When an unbalanced force acts on an object
xz_007 [3.2K]

Answer:

D. The object accelerates

Explanation:

3 0
3 years ago
If the voltage amplitude across an 8.50-nF capacitor is equal to 12.0 V when the current amplitude through it is 3.33 mA, the fr
xxTIMURxx [149]
<h2>Answer:</h2>

5.19 x 10³Hz

<h2>Explanation:</h2>

The capacitive reactance, X_{C}, which is the opposition given to the flow of current through the capacitor is given by;

X_C = \frac{1}{2\pi fC }

Where;

f = frequency of the signal through the capacitor

C = capacitance of the capacitor.

Also, from Ohm's law, the voltage(V) across the capacitor is given by the product of current(I) and the capacitive reactance. i.e;

V = I x X_{C}             [Substitute the value of

=> V = I x \frac{1}{2\pi fC}      [Make f the subject of the formula]

=> f = \frac{I}{2\pi VC}                    ---------------------(i)

From the question;

I = 3.33mA = 0.00333A

C = 8.50nF = 8.50 x 10⁻⁹F

V = 12.0V

Substitute these values into equation (i) as follows;

f = \frac{0.00333}{2 * 3.142 * 12.0 * 8.50 * 10^{-9}}            [Taking \pi = 3.142]

f = 5.19 x 10³Hz

Therefore, the frequency is closest to f = 5.19 x 10³Hz

4 0
3 years ago
Light travels
BlackZzzverrR [31]
Yep.  'a', 'b', and 'c' are all accurate.

Actually, 'b' doesn't go far enough.  Light is not only "faster than
anything else we know of", we now know that it's impossible for
anything with mass to ever hit that speed, so we can just quit looking. 
7 0
4 years ago
Sam stands on a 20 m high cliff and throws a 45 g rock with an initial velocity of 5 m/s [forward] to the water below. Use the c
storchak [24]

Answer:

v = 12.52 [m/s]

Explanation:

To solve this problem we must use the energy conservation theorem. Which tells us that potential energy is transformed into kinetic energy or vice versa. This is more clearly as the potential energy decreases the kinetic energy increases.

Ep = Ek

where:

Ep = potential energy [J] (units of joules]

Ek = kinetic energy [J]

Ep = m*g*h

where:

m = mass of the rock = 45 [g] = 0.045 [kg]

g = gravity acceleration = 9.81 [m/s²]

h = elevation = (20 - 12) = 8 [m]

Ek = 0.5*m*v²

where:

v = velocity [m/s]

The reference level of potential energy is taken as the ground level, at this level the potential energy is zero, i.e. all potential energy has been transformed into kinetic energy. In such a way that when the Rock has fallen 12 [m] it is located 8 [m] from the ground level.

m*g*h = 0.5*m*v²

v² = (g*h)/0.5

v = √(9.81*8)/0.5

v = 12.52 [m/s]

5 0
3 years ago
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