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SVETLANKA909090 [29]
2 years ago
7

In which scenario is work being done on an object?

Physics
1 answer:
Inessa [10]2 years ago
3 0

Answer:c

Explanation:

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if you went to the doctor 3 weeks ago && youre going back, will they have to measure your height and weigh you again?
tino4ka555 [31]
No, they usually will not. It also depends why you're going/why you went the first time.
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3 years ago
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A 1 kg flashlight is dropped from rest and falls to the floor without air resistance . At the point during its fall, when it is
alexgriva [62]

Answer:

The speed of the flashlight at that point is 3.7 m/s

Explanation:

When an object of mass M is at a height H above the ground, the potential energy of the object is:

U = M*H*g

Where g is the gravitational acceleration, g = 9.8 m/s^2

And for an object with velocity v, the kinetic energy is:

K = (M/2)*v^2

We know that when the flashlight of mass  1kg is 0.7 meters above the ground, the potential energy is equal to the kinetic energy, then:

M = 1kg

H = 0.7m

g = 9.8 m/s^2

Replacing these in the equations, we get:

U = K

(1kg)*(0.7m)*(9.8 m/s^2) = ((1kg)/2)*v^2

As the mass factor appears in both sides, we can remove it:

(0.7 m)*(9.8 m/s^2) = (v^2)/2

Now we can multiply both sides by 2:

2*(0.7 m)*(9.8 m/s^2) = v^2

Now let's apply the square root to both sides:

√(2*(0.7 m)*(9.8 m/s^2)) = v = 3.7 m/s

8 0
2 years ago
John heats 1 kg of soup from 25 °C to 70 °C for 15 minutes by a heater. How long does the same heater take to heat 1.5 kg of the
Mumz [18]

Answer:

30 minutes

Explanation:

Energy per time is constant, so:

E₁ / t₁ = E₂ / t₂

m₁C₁ΔT₁ / t₁ = m₂C₂ΔT₂ / t₂

(1 kg) C (70°C − 25°C) / 15 min = (1.5 kg) C (80°C − 20°C) / t

(1 kg) (45°C) / 15 min = (1.5 kg) (60°C) / t

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t = 30 min

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3 years ago
A tool that uses lenses to focus light and<br>create useful images<br>​
lianna [129]

the answer your looking for is Optical instrument.

5 0
3 years ago
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Moving current has electrical energy.
Inessa [10]
Yes, that’s true it has electrical energy
5 0
2 years ago
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