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icang [17]
2 years ago
15

The value of x in Fe(NH₂)₂(SO4)₂ xH₂O can be found by determining the amount in mol of sulfate in the compound. A 0.982 g sample

was dissolved in water and excess BaCl₂(aq) was added. The precipitate of BaSO, was separated and dried and found to weigh 1.17 g.
a) Calculate the amount, in mol, of BaSO4 in the 1.17 g of precipitate.

b) Calculate the amount, in mol, of sulfate in the 0.982 g sample of Fe(NH₂)₂(SO4)₂ XH₂O.

c) Calculate the amount, in mol, of iron in the 0.982 g sample of Fe (NH₂)₂(SO4)2 xH₂O.

d) Determine the mass, in g, of the following present in the 0.982 g sample of Fe(NH₂)₂(SO₂)₂ xXH₂O:

(i) iron (ii) ammonium (iii) sulfate.

e) Use your answer from part (d) to determine the amount in mol of water present in the 0.982 g sample of Fe(NH₂)₂(SO4)₂ xH₂O.
Chemistry
1 answer:
Shtirlitz [24]2 years ago
5 0

Answer: e

Explanation: ima be real i searched it up lol

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