Which situation would cause a red for an observer on the red planet?

If an alloy is formed that is 50 mol% silver and 50 mol% gold, what is the karat number of the alloy?

Allisa [31]

Answer : 12 karat

Explanation : When pure gold is considered to be 24 karat then if its 50 mol% silver and 50 mol% silver then using karat scale calculation;

Karat/24 X 100 = 50 mol% (for gold) in alloy

So, Karat = (50 X 24) / 100 = 12 karat.

Hence the alloy will be of 12 karat.

7 0

3 years ago

Read 2 more answers

When aluminum is placed in concentrated hydrochloric acid, hydrogen gas is produced. 2 Al ( s ) + 6 HCl ( aq ) ⟶ 2 AlCl 3 ( aq )

Dovator [93]

Answer:

The volume of hydrogen gas produced at STP is 4.90 liters.

Explanation:

$2Al (s) + 6 HCl (aq)\rightarrow 2 AlCl_3 (aq) + 3 H_2 (g)$

Moles of aluminium = $\frac{3.60 g}{27 g/mol}=0.1333 mol$

According to reaction , 2 moles of aluminium gives 3 moles of hydrogen gas.

Then 0.1333 moles of aluminium will give:

$\frac{3}{2}\times 0.1333 mol=0.2 moles$ of hydrogen gas

Volume of 0.2 moles of hydrogen gas at STP = V

Temperature at STP = T = 298.15 K

Pressure at STP = P = 1 atm

n = 0.2 mol

PV = nRT (Ideal gas equation)

$V=\frac{nRT}{P}=\frac{0.2mol\times 0.0821 atm L/mol K\times 298.15 K}{1 atm}=4.8956 L\approx 4.90 L$

The volume of hydrogen gas produced at STP is 4.90 liters.

4 0

3 years ago

Determine the empirical formula of a compound containing 48.38 grams of carbon, 6.74 grams of hydrogen, and 53.5 grams of oxygen

Darya [45]

Answer: The empirical formula of the compound becomes $CH_2O$

Explanation:

The empirical formula is the chemical formula of the simplest ratio of the number of atoms of each element present in a compound.

We are given:

Mass of C = 48.38 g

Mass of H = 6.74 g

Mass of O = 53.5 g

The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ......(1)

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Molar mass of C = 12 g/mol

Molar mass of H = 1 g/mol

Molar mass of O = 16 g/mol

Putting values in equation 1, we get:

$\text{Moles of C}=\frac{48.38g}{12g/mol}=3.023 mol$

$\text{Moles of H}=\frac{6.74g}{1g/mol}=6.74 mol$

$\text{Moles of O}=\frac{53.5g}{1g/mol}=3.34 mol$

Step 2: Calculating the mole ratio of the given elements.

Calculating the mole fraction of each element by dividing the calculated moles by the least calculated number of moles that is 3.023 moles

$\text{Mole fraction of C}=\frac{3.023}{3.023}=1$

$\text{Mole fraction of H}=\frac{6.74}{3.023}=2.23\approx 2$

$\text{Mole fraction of O}=\frac{3.34}{3.023}=1.105\approx 1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O = 1 : 2 : 1

Hence, the empirical formula of the compound becomes $CH_2O$

5 0

3 years ago

What mass of AI2O3 forms, knowing the molar mass of Al2O3 is 102 g/mol ?

TiliK225 [7]

Question

What mass of Al₂O₃ form is produced if 25.00 g of aluminum (al) is reacted completely?, knowing the molar mass of Al₂O₃ is 102 g/mol?

Atomic mass of Al =27 and O = 16

The molar mass of Al₂O₃ = 102.

Mass of aluminium in 102 g of Al₂O₃ = 54 g

54 g Al => 102 g Al₂O₃

25g Al => x g Al₂O₃

x = 25*102/54 = 47.2 g Al₂O₃

To solve more questions on molar mass check here:

brainly.com/question/21334167

3 0

1 year ago

Is it true that minerals come from orgainic

olga nikolaevna [1]

No but some minerals do

4 0

2 years ago