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2 years ago

What does the atomic mass number of each atom represent.

Chemistry

1 answer:

mariarad [96]2 years ago

3 0

The atomic mass number tells us the number of neutrons and protons in the nucleus of an atom.

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What is the mass % of iron in Fe(CH3CO2)2<br><br> (Fe=iron=55.85)

Serjik [45]

The mass percentage is 15.1465%.

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2 years ago

Which of the following is an irreversible physical change?

Yuliya22 [10]

Answer:

b) sharpening a pencil

Explanation:

If you melt lead, boil water, or dissolve sugar in water, you can return all of them back to their original state. If you sharpen a pencil, you can't reattach the shavings as they were originally.

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3 years ago

Complete this equation for the dissociation of NH4NO3(aq).

Delvig [45]

Dissociation
NH₄NO₃(aq) = NH₄⁺(aq) + NO₃⁻(aq)

the hydrolysis of the cation
NH₄⁺(aq) + H₂O(l) = NH₃(aq) + H₃O⁺(aq)
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2 years ago

Read 2 more answers

Which items are directly related to radioactive decay

uranmaximum [27]

E=mc^2 and mass defect

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2 years ago

4. Magnesium and oxygen undergo a chemical reaction to

erastovalidia [21]

Answer:

About 16.1 grams of oxygen gas.

Explanation:

The reaction between magnesium and oxygen can be described by the equation:
$\displaystyle 2\text{Mg} + \text{O$_2$} \longrightarrow 2\text{MgO}$

24.4 grams of Mg reacted with O₂ to produce 40.5 grams of MgO. We want to determine the mass of O₂ in the chemical change.

Compute using stoichiometry. From the equation, we know that two moles of MgO is produced from every one mole of O₂. Therefore, we can:

Convert grams of MgO to moles of MgO.
Moles of MgO to moles of O₂
And moles of O₂ to grams of O₂.

The molecular weights of MgO and O₂ are 40.31 g/mol and 32.00 g/mol, respectively.

Dimensional analysis:

$\displaystyle 40.5\text{ g MgO} \cdot \frac{1\text{ mol MgO}}{40.31\text{ g MgO}} \cdot \frac{1\text{ mol O$_2$}}{2\text{ mol MgO}} \cdot \frac{32.00\text{ g O$_2$}}{1\text{ mol O$_2$}} = 16.1\text{ g O$_2$}$

In conclusion, about 16.1 grams of oxygen gas was reacted.

You will obtain the same result if you compute with the 24.4 grams of Mg instead:

$\displaystyle 24.4\text{ g Mg}\cdot \frac{1\text{ mol Mg}}{24.31\text{ g Mg}} \cdot \frac{1\text{ mol O$_2$}}{1\text{ mol Mg}} \cdot \frac{32.00\text{ g O$_2$}}{1\text{ mol O$_2$}} = 16.1\text{ g O$_2$}$

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1 year ago