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Korolek [52]
2 years ago
14

CONCLUSIONS: Suppose a student titrated a sample of monoprotic acid of unknown concentration using a previously standardized sol

ution of NaOH. volume of 0.125 M NaOH dispensed 24.68 mL volume of acid solution 50.00 mL Given the data in the table above, what is the concentration of the unknown acid?
Chemistry
1 answer:
Zolol [24]2 years ago
3 0

Concentration of unknown acid is 0.061 M

Given:

Concentration of NaOH = 0.125 M

Volume of NaOH = 24.68 mL

Volume of acid solution = 50.00 mL

To Find:

Concentration of the unknown acid

Solution: Concentration is the abundance of a constituent divided by the total volume of a mixture. The concentration of the solution tells you how much solute has been dissolved in the solvent

Here we will use the formula for concentration:

M1V1 = M2V2

0.125 x 24.68 = 50 x M2

M2 = 0.125 x 24.68 / 50

M2 = 0.061 M

Hence, the concentration of unknown acid is 0.061 M

Learn more about Concentration here:

brainly.com/question/17206790

#SPJ4

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The balanced equation for the reaction between KOH and HF is 
KOH + HF ---> KF + H₂O
stoichiometry of KOH to HF is 1:1
the number of HF moles reacted - 0.20 mol/L x 0.1000 L = 0.020 mol
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KOH is a strong base and HF is a strong acid therefore they completely ionise into their corresponding ions
KOH --> K⁺ + OH⁻
HF ---> H⁺ + F⁻
number of H⁺ moles reacted = number of OH⁻ moles reacted
solution is completely neutralised no excess hydroxide or hydrogen ions
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pH of solution = 7
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