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3 years ago

What types of isomerism are exhibited by the coordination complex [co(dppe)(net3)2cl2] ?

Chemistry

1 answer:

mixer [17]3 years ago

3 0

Answer:

have you found the answer

Explanation:

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The ___ properties of elements repeat periodically when the ___ are arranged by ___ atomic number

Triss [41]

Answer:

The properties of elements will repeat periodically when the elements are arranged by their atomic number.

Explanation:

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3 years ago

When the ionic compound ammonium chloride, NH 4 Cl, , dissolves in water, it breaks into one ammonium ion, NHt^ 1+ , one chlorid

Arada [10]

Answer:

0.400 moles

Explanation:

Well, you know that one mole of ammonium chloride,

NH 4 Cl , dissociates completely in aqueous solution to form one mole of ammonium cations,

NH + 4 , and one mole of chloride anions, Cl − .

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3 years ago

How did Thomson show that cathode<br> rays are different from light?

Flura [38]

Answer:

They had a negative charge

Explanation:

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3 years ago

How is shielding effect related to atomic radius?

jolli1 [7]

Shielding effect being attendency of the inner electrons to repel the outermost electrons, an increase in shielding effect increases atomic radius and decrease reduces the atomic radius

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3 years ago

If 34.5 g of Copper reacts with 70.2 g of silver nitrate, according to the following

Vlada [557]

Answer:

44,55 can be produced.

Explanation:

First, we balanced the equation

1Cu + 2AgNO3 → 1Cu(NO3)2 + Ag

Then, we find the moles of each reagent

$mol Cu = \frac{34,5g}{63,55\frac{g}{mol} } = 0,543 mol\\$

$mol AgNO3 = \frac{70,2g}{169,87\frac{g}{mol} } = 0,413 mol\\$

Now, we find the limiting reagent from the quantities of product that can be formed from each reagent

$mol AgNO3= 0,543mol Cu . \frac{2 mol AgNo3}{1 mol Cu} = 1,086 mol$

$mol Cu= 0,413 mol AgNO3 . \frac{1 mol Cu}{2 mol AgNO3} = 0,206 mol$

1,086 moles of AgNO3 is necessary for each mole of Cu since we have 0.413 moles of Ag(NO3), the nitrate is the limiting reagent

the value of the limiting reagent determines the amount of product that is generated

∴ 0,413 mol of Ag can be produced

Ag = $0,413 mol . 107,87\frac{g}{mol}$ = 44,55g

Ag≈ 44,6g

4 0

4 years ago

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