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BaLLatris [955]
3 years ago
12

How many moles of calcium ion 40.0 g of calcium

Chemistry
1 answer:
VladimirAG [237]3 years ago
8 0
Look on this website! 
http://lawr.ucdavis.edu/classes/ssc100/CEC_Answers02.htm

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Whenever a number or a variable is divided<br> by itself, it is always equal to
Jobisdone [24]

Answer:itself

Explanation:

Duh

5 0
3 years ago
Sulfuric acid is essential to dozens of important industries from steelmaking to plastics and pharmaceuticals. More sulfuric aci
Pavlova-9 [17]

Given:

K = 0.71 = Kp

The reaction of sulphur with oxygen is

                            S(s)   + O2(g)  ---> SO2(g)

initial Pressure                   6.90         0

Change                                -x            +x

Equilibrium                     6.90-x          x

Kp = pSO2 / pO2 = 0.71 = x / (6.90-x)

4.899 - 0.71x  = x

4.899 = 1.71x

x = 2.86 atm = pressure of SO2 formed

temperature = 950 C = 950 + 273.15 K = 1223.15 K

Volume = 50 L

Let us calculate moles of SO2 formed using ideal gas equation as

PV = nRT

R = gas constant = 0.0821 L atm / mol K

putting other values

n = PV / RT = 2.86 X 50 / 1223.15 X 0.0821 = 1.42 moles

Moles of Sulphur required = 1.42 moles

Mass of sulphur required or consumed = moles X atomic mass of sulphur

mass of S = 1.42 X 32 = 45.57 grams or 0.04557 Kg  of sulphur



 


6 0
3 years ago
What is the hydrogen ion concentration of 0.450M solution of acetic acid (HC2H3O2), if the ionization constant(Ka) is 2.19 x 10-
WITCHER [35]

Answer:

3.02 Mm

Explanation:

3 0
3 years ago
The density of cadmium is 8.65 g/mL, what is the volume of a 33.4 g object made of pure cadmium?
Rzqust [24]

Answer:

Volume = 3.86 ml (Approx)

Explanation:

Given:

Density of cadmium = 8.65 g/ml

Mass of pure object = 33.4 g

Find:

Volume pure cadmium

Computation:

Volume = Mass / Density

Volume = 33.4 / 8.65

Volume = 3.86 ml (Approx)

6 0
3 years ago
What does photosynthesis mean?
AleksandrR [38]
Photosynthesis is the ability for a plant to turn light into energy, thus feeding it
6 0
3 years ago
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