Answer:
Since there are 3500 g of fuel left in the tank, and he needs only 1687.5 g to complete 20 laps, he has enough fuel to complete the race. I will tell the driver that he does not need to make another pit stop as he has enough fuel to complete the race.
Explanation:
Density = mass / volume
Density of fuel = 700 g/ 1 gal
Therefore, the mass of fuel in 1 gallon = 700 g
The driver has 5.0 gallons of fuel in the tank.
The mass of 5.0 gallons of fuel = 5 × 700 = 3500 g of fuel
Equation of the combustion of fuel, C₅H₁₂ is given below:
C₅H₁₂ + 8 O₂ ---> 6 H₂O + 5 CO₂
1 mole C₅H₁₂ requires 8 moles of O₂
1 mole of C₅H₁₂ has a mass = 72 g
8 moles of O₂ has a mass = 256 g
Therefore, 300 g of O₂ will require 300 × (72/256) g of C₅H₁₂ = 84.375 g of C₅H₁₂
84.375 g of fuel is used by the car per lap;
20 laps will require 20 × 84.375 g of fuel = 1687.5 g of fuel.
Since there are 3500 g of fuel left in the tank, and he needs only 1687.5 g to complete 20 laps, he has enough fuel to complete the race. I will tell the driver that he does not need to make another pit stop as he has enough fuel to complete the race.
