Question

A rock is dropped from a height of 100 feet. Calculate the time between when the rock was dropped and when it landed. If we choose "down" as positive and ignore air friction, the function is h (t) = 36t2 - 64
t= 3.56 seconds
t= 1.78 seconds
t= 1.33 seconds
t= 8 seconds

Answer 1

The time it takes between when the rock was dropped and when it landed is 1.33 seconds.

What is the time it takes for the rock to land?

The time it takes the rock to land on the ground from where it is dropped can be determined by using the function given.

The height of the function when it hits the ground will be zero, so the function can be written as:

$\mathbf{h(t) =36t^2 -64}$

$\mathbf{0 =36t^2 -64}$

64 = 36t²

$\mathbf{t^2 = \dfrac{64}{36}}$

t² =1.778

$t = \sqrt{1.778}$

t = 1.333 seconds

Learn more about calculating the time of a function here:

brainly.com/question/26898697

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