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Elanso [62]
3 years ago
13

If a person weighs 240 pounds on Earth, what would be the difference in weight of the same person on Mars and on the Moon

Mathematics
2 answers:
Vika [28.1K]3 years ago
4 0

Answer:

Mars: \Delta W = 144\,lbf, Moon: \Delta W = 199.2\,lbf

Step-by-step explanation:

The gravitational acceleration experimented by the same person on the Moon is equivalent to a sixth of the indicator on Earth and the same indicator on Mars is about 40 % of the terrestrial acceleration. Then, the difference in weight are computed below:

Mars:

\Delta W = (1 - 0.4) \cdot (240\,lbf)

\Delta W = 144\,lbf

Moon:

\Delta W = (1 - 0.17) \cdot (240\,lbf)

\Delta W = 199.2\,lbf

vlada-n [284]3 years ago
3 0
Because weight = mass x surface gravity, multiplying your weight on Earth by the numbers above will give you your weight on the surface of each planet. If you weigh 150 pounds (68 kg.) on Earth, you would weigh 351 lbs. (159 kg.) on Jupiter, 57 lbs. (26 kg.) on Mars and a mere 9 lbs. (4 kg.)
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6/13÷6/12=12/13 so C.

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marta [7]

Answer:

Step-by-step explanation:

a = \frac{2b+1}{3b-1}

b = 2/3

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a = 7/3

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\frac{2b+1}{3b-1}=a\\\\

Cross multiply,

2b + 1 = a*(3b - 1)

2b + 1 = a*3b - 3*a

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b =\frac{-3a - 1}{2 - 3a}

3 0
2 years ago
CUCI P
Free_Kalibri [48]

Answer:

$62.42

Step-by-step explanation:

1st step: Simplify the numbers first

$24.99 -------> 25

$12.99 ---------> 13

$4.49 ----------> 4

$19.95 ---------> 20

25+13+4+20= 62

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$0.42+ $62.00 = $62.42

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6 0
2 years ago
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Help me quick please --4x-7-3x+4=25
V125BC [204]

Answer:

<h2><em><u>x</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>32</u></em></h2>

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4x - 7 - 3x + 4 =25

=> 4x - 3x = 25 + 7

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3 years ago
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Suppose the number of radios in a household has a binomial distribution with parameters n=11 and p=40%. Find the probability of
Ivenika [448]

Answer:

Step-by-step explanation:

The formula for binomial distribution is expressed as

P(x=r) = nCr × q^(n-r) × p^r

From the information given,

n = 11

p = 40% = 40/100 = 0.4

q = 1 - 0.4 = 0.6

x represent the number of radios

a) P( x = 1) or P(x = 9)

P(x = 1) = 11C1 × 0.6^(11-1) × 0.4^1

P(x = 1) = 0.027

P(x = 9) = 11C9 × 0.6^(11-9) × 0.4^9

P(x = 9) = 0.0052

P( x = 1) or P(x = 9) = 0.027 + 0.0052 = 0.0322

b) P(x lesser than or equal to 7) = P(x = 0) + P(x = 1) + P(x = 2) + P(x = 3) + P(x = 4) + P(x = 5) + P(x = 6)

P(x = 0) = 11C0 × 0.6^(11-0) × 0.4^0 = 0.004

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P(x = 2) = 11C2 × 0.6^(11-2) × 0.4^2 = 0.089

P(x = 3) = 11C3 × 0.6^(11-3) × 0.4^3 = 0.177

P(x = 4) = 11C4 × 0.6^(11-4) × 0.4^4 = 0.24

P(x = 5) = 11C5 × 0.6^(11-5) × 0.4^5 = 0.22

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P(x lesser than or equal to 7) = 0.004 + 0.027 + 0.089 + 0.177 + 0.24 + 0.22 + 0.15 + 0.07 = 0.977

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d) P(x lesser than 9) = P(x lesser than or equal to 7) + P(x = 8)

P(x = 8) = 11C8 × 0.6^(11-8) × 0.4^8 = 0.02

P(x lesser than 9) = 0.977 + 0.02 = 0.997

e. P(x greater than 7) = 1 - P(x lesser than or equal to 7) = 1 - 0.977 = 0.023

5 0
3 years ago
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