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asambeis [7]
2 years ago
9

A wooden block has a mass of 55 grams, correct to the nearest gram. A) Find the least possible mass of the wooden block. B) The

volume of the wooden block is 19cm3, correct to the nearest cubic centimetre. Find the greatest possible mass of 1 cubic centimetre of the wood.​
Mathematics
1 answer:
Nina [5.8K]2 years ago
4 0

Answer:

A) 54.5g, B) 1.4g

Step-by-step explanation:

Find the lower bound of 55 and the upper bound of the cubed root of 1. the cubed root of 1 is 1 and the upper bound of that is 1.4

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Elodia [21]
I believe it would be 6 ounces
6 0
3 years ago
Sean b= 5,79; c= 10,4,el angulo A= 54,46°, el angulo C mide ?
Rzqust [24]

Answer:

C \approx 91.732^{\circ}

Step-by-step explanation:

(This exercise is presented in Spanish and for that reason explanation will be held in such language)

El lado restante se determina por la Ley del Coseno:

a = \sqrt{b^{2}+c^{2}-2\cdot b\cdot c \cdot \cos A}

a = \sqrt{5.79^{2}+10.4^{2}-2\cdot (5.79)\cdot (10.4)\cdot \cos 54.46^{\circ}}

a \approx 8.466

Finalmente, el angulo C se halla por medio de la misma ley:

\cos C = - \frac{c^{2}-a^{2}-b^{2}}{2\cdot a \cdot b}

\cos C = -\frac{10.4^{2}-8.466^{2}-5.79^{2}}{2\cdot (8.466)\cdot (5.79)}

\cos C = -0.030

C \approx 91.732^{\circ}

3 0
3 years ago
Samir is an expert marksman. When he takes aim at a particular target on the shooting range, there is a 0.950.950, point, 95 pro
Vinvika [58]

Answer:

40.1% probability that he will miss at least one of them

Step-by-step explanation:

For each target, there are only two possible outcomes. Either he hits it, or he does not. The probability of hitting a target is independent of other targets. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

0.95 probaiblity of hitting a target

This means that p = 0.95

10 targets

This means that n = 10

What is the probability that he will miss at least one of them?

Either he hits all the targets, or he misses at least one of them. The sum of the probabilities of these events is decimal 1. So

P(X = 10) + P(X < 10) = 1

We want P(X < 10). So

P(X < 10) = 1 - P(X = 10)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 10) = C_{10,10}.(0.95)^{10}.(0.05)^{0} = 0.5987

P(X < 10) = 1 - P(X = 10) = 1 - 0.5987 = 0.401

40.1% probability that he will miss at least one of them

7 0
3 years ago
If log a=3 log b-2 log c, find an expression for a that does not involve logarithms​
photoshop1234 [79]

Assuming that b>0 and c>0:

log(a)=3×log(b)-2×log(c)=

log(b³)-log(c²)=

log(b³/c²)

Hence a=b³/c²

7 0
3 years ago
Please help! Brainliest if you explain
My name is Ann [436]
Switch sides

4/5 (x+3)=y+6

Multiply both sides by 5

5*4/5 (x+3) = 5y+5*6

Simplify

4(x+3) = 57+30

Divide both sides by 4

4(x+3)/4 = 5y/4+ 30/4

Simplify

x+3 = 5y+30/4 

Subtract 3 from both sides

x+3 - 3 = 5y+30/4 - 3

Simplify 

x=5y+30/4 - 3











3 0
3 years ago
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