Question

A smart-phone is thrown upwards from the top of a 384-foot building with an initial velocity of 32 feet per

Answer 1

Answer:

When t = 4

Step-by-step explanation:

The phone will hit the ground when h = 0.

$16t^2 + 32t + 384 =0 \\ \\ t^2 + 2t + 24=0 \\ \\ (t+6)(t-4)=0 \\ \\ t=-6, 4$

However, as time cannot be negative, we know the answer is when t = 4.