This table represents a quadratic function with a vertex at (1, 0). What is the

Mathematics

1 answer:

inn [45]1 year ago

7 0

Answer:

Step-by-step explanation:

You might be interested in

Polygon ABCD has the following vertices:

Nutka1998 [239]

I believe its D hope this helps

4 0

3 years ago

Terrance claims that for the input coordinates (x, y), a rotation of 180° clockwise about the origin, followed by a reflection o

vodka [1.7K]

Answer:

Terrance is incorect.

Correct output coordinates (-y,-x)

Step-by-step explanation:

Let $(x,y)$ be the input coordinates.

First translation is a rotation of 180° clockwise about the origin. This translation has a rule

$(x,y)\rightarrow (-x,-y)$

Second translation is a reflection over the line y = x. The general rule for the reflection across the line y=x has the rule

$(a,b)\rightarrow (b,a)$

When a sequence of two translations are applied to the initial input coordinates, then

$(x,y)\rightarrow (-x,-y)\rightarrow (-y,-x)$

As you can see Terrance made a mistake and these two transformations do not cancel themselves out.

8 0

3 years ago

Is this the right answer?

Aliun [14]

Answer:

yep the Answer is right

5 0

3 years ago

I need help solving this problem

Elena L [17]

Use the given values in the compound interest formula to solve for time, n.

A is the final amount of money, $2800
P is the initial or starting amount $1900
i is the interest rate as a decimal 0.025
n is time in years since it annual.

2800 = 1900(1 + 0.025)^n

2800 = 1900(1.025)^n

2800/1900 = (1.025)^n

28/19 = (1.025)^n

take the natural log of both sides to solve for exponent.

ln(28/19) = ln(1.025^n)

power rule of logarithmic moves exponent

ln(28/19) = n*ln(1.025)

ln(28/19) / ln(1.025) = n

put into a calculator

15.7 years = n

4 0

3 years ago

Evaluate limit:<br> lim x approaches 0 e^(5x)-1-5x/x^2

rosijanka [135]

Lim as x approches 0 of (e^(5x) - 1 - 5x)/x^2 = lim as x approaches 0 of (5e^(5x) - 5)/2x = lim as x approaches 0 of 25e^(5x)/2 = 25/2 = 12.5

8 0

3 years ago