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AveGali [126]
2 years ago
7

A generic element, Q, has two isotopes, 195Q and 190Q, and an average atomic mass of 191.86 amu. The natural abundances of the t

wo isotopes are 38% 195Q and 62% 190Q. The isotopic mass of 195Q is 194.96 amu. What is the isotopic mass of 190Q
Chemistry
1 answer:
Lera25 [3.4K]2 years ago
3 0

A generic element, Q, has two isotopes, 195Q and 190Q, and an average atomic mass of 191.86 amu. The natural abundances of the two isotopes are 38% 195Q and 62% 190Q. The isotopic mass of 195Q is 194.96 amu.  the isotopic mass of 190Q is 186.80.

<h3>What do you mean by Isotopes?</h3>

Isotopes are two or more atom types that share the same atomic number (number of protons in their nuclei), location in the periodic table, and chemical element but have distinct nucleon numbers (mass numbers) as a result of having a different number of neutrons in their nuclei. Although the chemical properties of each isotope of a given element are nearly identical, they differ in their atomic weights and physical characteristics.

191.86 =(62% x 194.96 + 38% x  X )

where, X is the mass of other Isotope.

X     = (191.86  - 120.8752)/0 .38

       = 186.80

<h3>Parent and Daughter Isotopes</h3>

The initial radioisotope and the isotope that results from radioactive decay may not be the same. The atoms created by the reaction are known as daughter isotopes, whereas the original isotope is known as the parent isotope. It's possible to get different kinds of daughter isotopes.

As an illustration, the uranium atom is the parent isotope and the thorium atom is the daughter isotope when U-238 decays into Th-234.

Learn more about Isotopes here:-

brainly.com/question/27407210

#SPJ4

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A reaction produces 0.829 moles of H2O. How many molecules are produced?
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if the Celsius temperature of a gas at constant pressure is increased from 10 Celsius to 20 Celsius the volume is
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Explanation:

                     According to <em>Charles' Law</em>, " <em>at constant pressure the volume and temperature of the gas are directly proportional to each other</em>". Mathematically this law is presented as;

                                                    V₁ / T₁ = V₂ / T₂   -----(1)

In statement the data given is,

T₁  =  10 °C  =  283.15 K                    ∴  K  =  273.15 + °C

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So, it is clear that the temperature is being increased hence, we will find an increase in volume. Let us assume that the starting volume is 100 L, so,

V₁  =  100 L

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                                     V₂  = 100 L × 293.15 K / 283.15 K

                                     V₂  = 103.52 L

Hence, it is proved that by increasing temperature from 10 °C to 20 °C resulted in the increase of Volume from 100 L to 103.52 L.

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