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Luba_88 [7]
3 years ago
7

if the Celsius temperature of a gas at constant pressure is increased from 10 Celsius to 20 Celsius the volume is

Chemistry
1 answer:
svet-max [94.6K]3 years ago
3 0

Answer:

               The volume is increased.

Explanation:

                     According to <em>Charles' Law</em>, " <em>at constant pressure the volume and temperature of the gas are directly proportional to each other</em>". Mathematically this law is presented as;

                                                    V₁ / T₁ = V₂ / T₂   -----(1)

In statement the data given is,

T₁  =  10 °C  =  283.15 K                    ∴  K  =  273.15 + °C

T₂  =  20 °C  =  293.15 K

So, it is clear that the temperature is being increased hence, we will find an increase in volume. Let us assume that the starting volume is 100 L, so,

V₁  =  100 L

V₂  =  Unknown

Now, we will arrange equation 1 for V₂ as,

                                                    V₂  =  V₁ × T₂ / T₁

Putting values,

                                     V₂  = 100 L × 293.15 K / 283.15 K

                                     V₂  = 103.52 L

Hence, it is proved that by increasing temperature from 10 °C to 20 °C resulted in the increase of Volume from 100 L to 103.52 L.

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6 0
3 years ago
Point E is located at (-2, 2) and point F is located at (4-6). What is the distance between
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Answer:

10

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To find the distance between two points;

   Use the expression below;

 D = \sqrt{(y_{2} - y_{1}  )^{2} + (x_{2} -  x_{1})^{2}  }

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4 0
3 years ago
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baherus [9]

Answer:

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Explanation:

Using ideal gas equation as:

PV=nRT

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P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 62.3637\text{ L.mmHg }mol^{-1}K^{-1}

Also,  

Moles = mass (m) / Molar mass (M)

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So, the ideal gas equation can be written as:

PM=dRT

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Applying the equation as:

P × 28 g/mol  = 1.80 g/L × 62.3637 L.mmHg/K.mol × 305.15 K

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