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2 years ago

Which of the following is a true proportion of the figure based on the triangle

Mathematics

1 answer:

Anni [7]2 years ago

4 0

Based on the triangle proportionality theorem, the true proportion is h/j=k/i

<h3>How to solve for the true proportion</h3>

In the diagram that we have here, we have TU to be parallel to QR.

We have following

ST is equal to h, TQ is equal to j, SU is equal to k and UR is equal to i.

This can then be used to form the equation

ST/TQ = SU/UR

When we h/j = k/i

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The oblique rectangular prism below has a length of 6 cm, a width of 8 cm, and a height of 7 cm. An oblique rectangular prism ha

Dvinal [7]

Answer:

48 cm²

Step-by-step explanation:

They are only asking for the area of the base of the prism, which is the length of the prism times the width of the prism.

B = area of base

l = length = 6 cm

w = width = 8 cm

B = l * w

B = 6 cm * 8 cm

B = 48 cm²

The area of the base of the prism is 48 cm²

6 0

3 years ago

Read 2 more answers

Rationalise 3 square root 2 divided by square root 3

Fofino [41]

Answer:

root3

Step-by-step explanation:

multiply the numerator and denominator by the root of 3

3root2×root3/root3×root3

3root6/3

note root3×root3=3

the 3 up will divide the 3 down

and that lives u with the answer root2

sorry currently won't have a way of writing the roots thats y am using words

7 0

3 years ago

The point P(1,1/2) lies on the curve y=x/(1+x). (a) If Q is the point (x,x/(1+x)), find the slope of the secant line PQ correct

lukranit [14]

Answer:

See explanation

Step-by-step explanation:

You are given the equation of the curve

$y=\dfrac{x}{1+x}$

Point $P\left(1,\dfrac{1}{2}\right)$ lies on the curve.

Point $Q\left(x,\dfrac{x}{1+x}\right)$ is an arbitrary point on the curve.

The slope of the secant line PQ is

$\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{\frac{x}{1+x}-\frac{1}{2}}{x-1}=\dfrac{\frac{2x-(1+x)}{2(x+1)}}{x-1}=\dfrac{\frac{2x-1-x}{2(x+1)}}{x-1}=\\ \\=\dfrac{\frac{x-1}{2(x+1)}}{x-1}=\dfrac{x-1}{2(x+1)}\cdot \dfrac{1}{x-1}=\dfrac{1}{2(x+1)}\ [\text{When}\ x\neq 1]$