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patriot [66]
1 year ago
8

In the following neutralization reaction 2CsOH(aq) H2SO4(aq), the salt produced will be _______________

Chemistry
1 answer:
lorasvet [3.4K]1 year ago
4 0

The salt produced by the neutralization of 2CsOH(aq) and H₂SO₄(aq) is Cesium Sulphate - Cs₂SO₄.

<h3>What is neutralization reaction?</h3>
  • The neutralization reaction takes place between an acid and a base to produce a salt and water.
  • The salt formed in the neutralization process is an ionic compound that consisting of an anion from the acid and a cation from the base.

<h3>Neutralization reaction for the given compounds:</h3>

The given compounds are

2CsOH - a strong base and H₂SO₄ - a strong acid

When they react with one another, the neutralization takes place and forms a neutral compound Cs₂SO₄ called as a salt.

The reaction is as follows:

2CsOH(aq) + H₂SO₄ → Cs₂SO₄ + H₂O

Therefore, the salt produced will be Cs₂SO₄(Cesium sulphate).

Learn more about neutralization here:

brainly.com/question/203541

#SPJ4

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The Ksp of calcium carbonate in water at 25 °C is 2.25 x 10-8. CaCO3(s) &lt;----&gt; Ca2+ (aq) + CO3 2- (aq) What is favored at
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Answer:

the solubility of CaCO3 is 0.015g/l 25 °C

is favored at equilibrium

Explanation:

The Ksp of calcium carbonate in water at 25 °C is 2.25 x 10-8. CaCO3(s) <----> Ca2+ (aq) + CO3 2- (aq) What is favored at equilibrium?

solubility is the property of a solute to dissolve in a solvent(liquid, gas ) to form a solution(soution can be saturated ,unsaturated, or supersaturated)

CaCO3(s) <----> Ca2+ (aq) + CO3 2- (aq)

in partial dissociation , we can say

2.25x 10^-8=Ca^{2+} +CO^{2-}_{3} }

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2.25x10^-8=S*S

S^2=2.25x10^-8

S=0.00015mol/L

Converting that to g/l

the relative molecular mass of CaCO3=100g/mol

0.00015*100g/mol

0.015g/l

the solubility of CaCO3 is 0.015g/l @room temperature

is favored   at equilibrium

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