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patriot [66]
2 years ago
8

In the following neutralization reaction 2CsOH(aq) H2SO4(aq), the salt produced will be _______________

Chemistry
1 answer:
lorasvet [3.4K]2 years ago
4 0

The salt produced by the neutralization of 2CsOH(aq) and H₂SO₄(aq) is Cesium Sulphate - Cs₂SO₄.

<h3>What is neutralization reaction?</h3>
  • The neutralization reaction takes place between an acid and a base to produce a salt and water.
  • The salt formed in the neutralization process is an ionic compound that consisting of an anion from the acid and a cation from the base.

<h3>Neutralization reaction for the given compounds:</h3>

The given compounds are

2CsOH - a strong base and H₂SO₄ - a strong acid

When they react with one another, the neutralization takes place and forms a neutral compound Cs₂SO₄ called as a salt.

The reaction is as follows:

2CsOH(aq) + H₂SO₄ → Cs₂SO₄ + H₂O

Therefore, the salt produced will be Cs₂SO₄(Cesium sulphate).

Learn more about neutralization here:

brainly.com/question/203541

#SPJ4

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Zn + O2= ZnO<br><br> How many moles of zinc are needed to make 500. g of zinc oxide?​
s2008m [1.1K]

Answer:

5.15 moles

Explanation:

2zn + o2 = 2zno

5.15 2.57 5.15 moles

nzno=500/(16x2+65)= 5.15 moles

-> nzn = 5.15 x 2 ÷ 2 = 5.15 moles

6 0
3 years ago
25.0 mL of a hydrofluoric acid solution of unknown concentration is titrated with 0.200 M NaOH. After 20.0 mL of the base soluti
lesantik [10]

Answer:

[HF]₀ = 0.125M

Explanation:

NaOH + HF => NaF + H₂O

Adding 20ml of 0.200M NaOH into 25ml of HF solution neutralizes 0.004 mole of HF leaving 0.004 mole NaF in 0.045L with 0.001M H⁺ at pH = 3.   This is 0.089M NaF and 0.001M HF remaining.

=> 45ml of solution with pH = 3 and contains 0.089M NaF from titration becomes a common ion problem.

                HF  ⇄    H⁺    +      F⁻

C(eq)       [HF]     10⁻³M      0.089M (<= soln after adding 20ml 0.200M NaOH)

Ka = [H⁺][F⁻]/[HF]₀ => [HF]₀ = [H⁺][F⁻]/Ka

[HF]₀ = (0.001)(0.089)/(7.1 x 10⁻⁴) M = 0.125M

6 0
3 years ago
This represents three steps of the rock cycle. The sediments are layered and compressed in sedimentary rock. The sedimentary roc
Ber [7]

ANSWER: C) Law of Conservation of Mass

EXPLANATION: In the given cycle, it is seen that th sediments are layered and gets compressed into sedimentary rocks which eventually gets heated and compressed to form metamorphic rocks. But, the total amount of minerals present in the sediments remains the same throughout any stage of the cycle.

This proves the law of conservation of mass which states that mass can not be created nor be destroyed, it can only be transferred from one form to another. So, in this case, only phase transition occurred but the component which is mineral inside the sediments remains constant.

Therefore, the answer is law of conservation of mass.

4 0
3 years ago
Read 2 more answers
A box has 2 cm length, 3 cm width and 2 cm height. What is its volume? *
Valentin [98]
12cm cubed.
Formula is length x width x height and in this case it would be 2x3x2 which equals 23
3 0
3 years ago
Read 2 more answers
A lead sphere has a mass of 1.20 x 104 g, and its volume is 1.05 x 103 cm^3. Calculate the density of lead.
Hatshy [7]

Answer: The density of lead will be 11.42g/cm^3

Explanation:

Density is defined as the mass contained per unit volume.

Density=\frac{mass}{Volume}

Given : Mass of lead=1.20\times 10^4g

Volume of lead =1.05\times 10^3cm^3

Putting in the values we get:

Density=\frac{1.20\times 10^4}{1.05\times 10^3}=11.42g/cm^3

Thus density of lead will be 11.42g/cm^3

4 0
3 years ago
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