Answer:
The final temperature of both substances when they reach thermal equilibrium is 31.2 °C
Explanation:
Step 1: Data given
Mass of sample granite = 14.4 grams
Initial temperature = 86.0 °C
Mass of water = 24.0 grams
The initial temperature of water = 25.0 °C
The specific heat of water = 4.18 J/g°C
The specific heat of granite = 0.790 J/g°C
Step 2: Calculate the final temperature
Heat lost = heat gained
Qgranite = - Qwater
Q = m*c*ΔT
m(granite)*c(granite)*ΔT(granite) = -m(water)*c(water)*ΔT(water)
⇒with m(granite) = the mass of granite = 14.4 grams
⇒with c(granite) = The specific heat of granite = 0.790 J/g°C
⇒with ΔT⇒(granite) = the change of temperature of granite = T2 - T1 = T2 - 86.0 °C
⇒with m(water) = the mass of water = 24.0 grams
⇒with c(water) = The specific heat of water = 4.18 J/g°C
⇒with ΔT(water) = the change of temperature of granite = T2 - T1 = T2 -25.0°C
14.4 grams * 0.790 * (T2 - 86.0°C) = -24.0 *4.18 * (T2 - 25.0°C)
11.376T2 - 978.336 = -100.32T2 + 2508
111.696 T2 = 3486.336
T2 = 31.2 °C
The final temperature of both substances when they reach thermal equilibrium is 31.2 °C
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