The molecular formula for hyponitrous acid is H2N2O2. and for nitroxyl is HNO.
The chemical compound HNO is also known as nitroxyl (common name) or Azanon (IUPAC name). In the gas phase, it is widely recognized. In the solution phase, the short-lived intermediate nitroxyl can develop. Nitric oxide (NO) is reduced to form the conjugate base, NO, which is isoelectronic with dioxygen.
By oxidizing hydroxylamine with CuO , HgO, and Ag 2 and by oxidizing hydroxylamine with N2O3 in methyl-alcoholic solution, we can create hyponitrous acid.
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Answer:
In a voltaic cell (one that happens spontaneously), electrons flow from a negative electrode to a positive electrode (anode cathode). The reaction that happens is a redox reaction where the anode is oxidized (goes from a solid to an ion) and the cathode is reduced (going from an ion to a solid).
Explanation:
N⁻²2H4(l) + 2H2O⁻¹2(l) → N⁰2(g) + 4H2O⁻²(g)
N is oxidized and O is reduced
Answer:
0.29mol/L or 0.29moldm⁻³
Explanation:
Given parameters:
Mass of MgSO₄ = 122g
Volume of solution = 3.5L
Molarity is simply the concentration of substances in a solution.
Molarity = number of moles/ Volume
>>>>To calculate the Molarity of MgSO₄ we find the number of moles using the mass of MgSO₄ given.
Number of moles = mass/ molar mass
Molar mass of MgSO₄:
Atomic masses: Mg = 24g
S = 32g
O = 16g
Molar mass of MgSO₄ = [24 + 32 + (16x4)]g/mol
= (24 + 32 + 64)g/mol
= 120g/mol
Number of moles = 122/120 = 1.02mol
>>>> From the given number of moles we can evaluate the Molarity using this equation:
Molarity = number of moles/ Volume
Molarity of MgSO₄ = 1.02mol/3.5L
= 0.29mol/L
IL = 1dm³
The Molarity of MgSO₄ = 0.29moldm⁻³
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