X of moles/2.5L =0.50 M NaCl solution
X of moles = 2.5 * 0.5
X = 1.25 moles
Rounding with significant digits
1.3 mol
False ..............................................
Answer:
4.767 grams of KCl are produced from 2.50 g of K and excess Cl2
Explanation:
The balanced equation is
2 K+ Cl2 --->2 KCI
Here the limiting agent is K. Hence, the amount of KCl will be calculated as per the mass of 2.50 gram of K
Mass of one atom/mole of potassium is 39.098 grams
Number of moles is 2.5 grams = 
So, 2 moles of K produces 2 moles of KCL
0.064 moles of K will produces 0.064 moles of KCl
Mass of one molecule of KCl is 74.5513 g/mol
Mass of 0.064 moles of KCl is 4.767 grams
Answer:
D = 4 g/mL
General Formulas and Concepts:
Density = Mass over Volume
Explanation:
<u>Step 1: Define</u>
m = 100 g
V = 25 mL
D = unknown
<u>Step 2: Find D</u>
- Substitute: D = 100 g/25 mL
- Evaluate: D = 4 g/mL
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