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1 year ago

Honestly don’t know this ?

Mathematics

1 answer:

jarptica [38.1K]1 year ago

4 0

1 ) 6

2) 6

3) -2

4) 2

5) -2

6) 2

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Please help i am super confused and it is worth a lot of points !!!!<br><br> Find the measure of

garri49 [273]

Answer:

its probably around 110* or 100

Step-by-step explanation:

3 0

2 years ago

A=2(L+W) solve for W

balu736 [363]

First you divide L+W by 2 and you would get A/2=L+W then you would subtract L and get A/2 -L=W

7 0

3 years ago

Whats the answer? <br> and how did I get my answer?

Kamila [148]

Answer:

40°

Step-by-step explanation:

Angle 1 and Angle 2 are corresponding angles.

Corresponding angles are congruent, so 3x + 4 = 5x - 20

Solving 3x + 4 = 5x - 20

3x = 5x - 24

2x = 24

x = 12

Substitute angle 1

3x + 4 = 36 + 4 = 40

7 0

2 years ago

Carloshas1.2 meters of wood if cut into 3 equal pieces how many mm each

sdas [7]

1.2 ÷ 3 = 0.4 meters each
0.4 meters = 40 cm
40 cm = 400 mm

therefore,
Carlos must cut each piece of wood 400 mm each.

Hope this helps and have a great day! :D

5 0

2 years ago

5^(-x)+7=2x+4 This was on plato

Setler79 [48]

Answer:

Below

I hope its not too complicated

$x=\frac{\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)}{\ln \left(5\right)}+\frac{3}{2}$

Step-by-step explanation:

$5^{\left(-x\right)}+7=2x+4\\\\\mathrm{Prepare}\:5^{\left(-x\right)}+7=2x+4\:\mathrm{for\:Lambert\:form}:\quad 1=\left(2x-3\right)e^{\ln \left(5\right)x}\\\\\mathrm{Rewrite\:the\:equation\:with\:}\\\left(x-\frac{3}{2}\right)\ln \left(5\right)=u\mathrm{\:and\:}x=\frac{u}{\ln \left(5\right)}+\frac{3}{2}\\\\1=\left(2\left(\frac{u}{\ln \left(5\right)}+\frac{3}{2}\right)-3\right)e^{\ln \left(5\right)\left(\frac{u}{\ln \left(5\right)}+\frac{3}{2}\right)}$

$Simplify\\\\\mathrm{Rewrite}\:1=\frac{2e^{u+\frac{3}{2}\ln \left(5\right)}u}{\ln \left(5\right)}\:\\\\\mathrm{in\:Lambert\:form}:\quad \frac{e^{\frac{2u+3\ln \left(5\right)}{2}}u}{e^{\frac{3\ln \left(5\right)}{2}}}=\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}$

$\mathrm{Solve\:}\:\frac{e^{\frac{2u+3\ln \left(5\right)}{2}}u}{e^{\frac{3\ln \left(5\right)}{2}}}=\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}:\quad u=\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)\\\\\mathrm{Substitute\:back}\:u=\left(x-\frac{3}{2}\right)\ln \left(5\right),\:\mathrm{solve\:for}\:x$

$\mathrm{Solve\:}\:\left(x-\frac{3}{2}\right)\ln \left(5\right)=\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right):\\\quad x=\frac{\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)}{\ln \left(5\right)}+\frac{3}{2}$

3 0

3 years ago