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2 years ago

Gelatin Methacryloyl Hydrogels in the Absence of a Crosslinker as 3D Glioblastoma Multiforme (GBM)-Mimetic Microenvironment

1 answer:

4 0

For the eradication of malignancies like the aggressive type of human brain tumour known as glioblastoma multiforme (GBM), 3D platforms are crucial for tracking tumour growth and assessing treatment candidates.

<h3>What is Glioblastoma Multiforme (GBM)?</h3>

Glioblastoma (GBM), commonly known as a grade IV astrocytoma, is an aggressive brain tumour that grows quickly. The local brain tissue gets invaded, but it typically does not spread to distant organs. GBMs can develop from lower-grade astrocytomas or develop from new brain tumours.

Some characteristics of GBM are-

We explore cellular behavior, expression profiles of malignancy, and apoptosis-related genes within this novel network using suspension and spheroid-based models of GBM.
In-depth research is also done on the sensitivity to the anticancer medication Digitoxigenin.
According to the research, GelMA hydrogels contain high levels of prosurvival Bcl-2 gene expression and sparse or spheroid U373 cells, which have much lower expressions of apoptosis-activating genes like Bad, Puma, and Caspase-3.
The up regulation of matrix-metalloproteinase genes within GelMA suggests that gels have a beneficial effect on the extracellular remodelling of cancer cells.
Through the investigation of 3D malignant cancer cell behavior, this special photo curable gelatin shows significant promise for the practical translation of cancer research and, consequently, for more effective treatment techniques for GBM.

To know more about brain tumour, here

brainly.com/question/13606763

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Alex saved x dollars.

steposvetlana [31]

Answer:
Ethan = 1.(3x)

Step-by-step explanation:
Let's split "Ethan saved 1/3 more than that"
That = x
So, Ethan saved 1/3 more than x
Meaning that Ethan = x + 1/3x
Combine like terms
Ethan = 1 1/3x
which equals to
Ethan = 1.(3x)

Hope this helps :)
Have a great day

4 0

2 years ago

a volley ball player servers the ball. The ball follows a path given by the equation y=-0.01x^2+0.5x+3 where x and y are measure

dolphi86 [110]

Answer:

(a)

Distance from player should be 13.82 feet or 36.2 feet

(b)

The ball will go over the net

Step-by-step explanation:

we are given

The ball follows a path given by the equation

$y=-0.01x^2+0.5x+3$

where

x and y are measured in feet and the origin is on the court directly below where the player hits the ball

(a)

net height is 8 ft

so, we can set y=8

and then we can solve for x

$8=-0.01x^2+0.5x+3$

$8\cdot \:100=-0.01x^2\cdot \:100+0.5x\cdot \:100+3\cdot \:100$

$800=-x^2+50x+300$

$-x^2+50x-500=0$

$x^2-50x+500=0$

we can use quadratic formula

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$x=\frac{-50\pm \sqrt{50^2-4\left(-1\right)\left(-500\right)}}{2\left(-1\right)}$

$x=5\left(5-\sqrt{5}\right),\:x=5\left(5+\sqrt{5}\right)$

$x=13.82,x=36.2$

So, distance from player should be 13.82 feet or 36.2 feet

(b)

we can plug x=30 and check whether y=8 ft

$y=-0.01(30)^2+0.5(30)+3$

$y=9ft$

we know that

height of net is 8 ft

so, the ball will go over the net

5 0

3 years ago

Simon has a scale model of the Concorde airplane. The actual length of the Concorde is approximately 200 feet. If the ratio of t

Verizon [17]

The answer is: "40 cm " .
_________________________________________________________
<u>Note</u>:
_________________________________________________________

$\frac{200 ft }{ (x) cm} = \frac{5}{1}$ ;

Solve for "x" (in "cm" ) ;

→ 5x = 200 * 1 ;

→ 5x = 200 ;

Divide each side of the equation by "5" ;
to isolate "x" on one side of the equation; & to solve for "x" ;

→ 5x / 5 = 200 / 5 ;

to get:

→ x = 40 .
___________________________________________________________
The answer is: " 40 cm " .
___________________________________________________________

6 0

3 years ago

Read 2 more answers

Two lines and a point are guaranteed to be complainer if

Alexxandr [17]

I am here wondering watin dey do now aa

7 0

3 years ago

USE the RULE (x,y) -----> (x - 2, y - 4) to graph the image of this rectangle.

Olin [163]

So for example B(4,1) so x=4, y=1
->B'(4-2,1-4)
->B'(2,-3)

->A'(1-2,1-4)
->A'(-1,-3)

->C'(4-1,-2-4)
->C'(3,-6)

->D'(1-2,-2-4)
->D'(-1,-6)

so the image of the rectangle ABCD->A'B'C'D'

3 0

3 years ago