1 pound = 16 ounces
2 pounds x 16 ounces = 32 ounces for the peaches.
32 ounces - 14 ounces = 18
The peaches weigh 18 more ounces.
Answer:
B. y=7x+3
Step-by-step explanation:
You find the changes of y over the changes of x. y sub 2 - y sub 1 divided by x sub 2 over x sub 1. So, 17 - 10 over 2 - 1 = 7. 3 is the y-intercept. y=7x+3
-2x^4 + 24x^2 - 10
u have 3 terms.....and since u are only dealing with 1 variable with the highest exponent being 4, then what u have here is a 4th degree trinomial.
U have a lead coefficient of -2.
Ur constant term is -10
And ur middle term (24x^2) has a degree of 2
a cubic binomial.....a binomial has 2 terms and it being cubic means the highest term has a degree of 3
example would be : x^3 - 4
how many constants can a polynomial have ? I am not sure about this one...I wanna say 1 because u can simplify it if it has more then 1...but I am not 100% sure on this one
3x^2 + 6xy -10x^5 + y^6 - 10x^3y^5
when u have a polynomial with more then 1 variable, such as this one, the degree is not the highest exponent, it is the highest term.....-10x^3y^5...u add the exponents....so this term has a degree of 8, and it is the highest one in this problem....so this is an 8th degree polynomial with 5 terms
Answer:
Step-by-step explanation:
It is convenient to memorize the trig functions of the "special angles" of 30°, 45°, 60°, as well as the way the signs of trig functions change in the different quadrants. Realizing that the (x, y) coordinates on the unit circle correspond to (cos(θ), sin(θ)) can make it somewhat easier.
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<h3>20.</h3>
You have memorized that cos(x) = (√3)/2 is true for x = 30°. That is the reference angle for the 2nd-quadrant angle 180° -30° = 150°, and for the 3rd-quadrant angle 180° +30° = 210°.
Cos(x) is negative in the 2nd and 3rd quadrants, so the angles you're looking for are
150° and 210°
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<h3>Bonus</h3>
You have memorized that sin(π/4) = √2/2, and that cos(3π/4) = -√2/2. The sum of these values is ...
√2/2 + (-√2/2) = 0
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<em>Additional comments</em>
Your calculator can help you with both of these problems.
The coordinates given on the attached unit circle chart are (cos(θ), sin(θ)).
Answer:
![\sqrt[5]{13^3} = 13^{\frac{3}{5}}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B13%5E3%7D%20%3D%2013%5E%7B%5Cfrac%7B3%7D%7B5%7D%7D)
Step-by-step explanation: