Gravitational acceleration aka Weight
Answer:
Explanation:
Time period of the revolution of the disc is given as
now the angular speed of the disc is given as
so we will have
now at the rim position of the disc the net force on the penny is due to friction force
So we will have
here we will have
Hi there!
Question 1:
We know that Impulse = Δp = mΔv, so:
I = 0.045(70) = 3.15 Ns
I = F · t, so:
3.15/0.1 = F
F = 31.5 N
Question 2.
We can find the impulse using:
I = Ft
I = 300 · 0.04 = 12 Ns
Find the change in velocity using:
I = mΔv
12/0.13 = Δv = 92.31 m/s
Time = (distance) / (speed)
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Time = (450 km) / (100 m/s)
Time = (450,000 m) / (100 m/s)
Time = <em>4500 seconds </em>(that's 75 minutes)
Note:
This is about HALF the speed of the passenger jet you fly in when you go to visit Grandma for Christmas.
If the International Space Station flew at this speed, it would immediately go ker-PLUNK into the ocean.
The speed of the International Space Station in its orbit is more like 3,100 m/s, not 100 m/s.
