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Nutka1998 [239]
2 years ago
15

Because stalin feared western capitalist expansion, he

SAT
1 answer:
mote1985 [20]2 years ago
3 0

Because Stalin feared Western capitalist expansion, he refused to allow free elections in Eastern Europe.

<h3>What is Capitalism?</h3>

This refers to the economic system where businesses are allowed to thrive in a free market system with the main aim of making a profit.

Hence, we can see that based on the difference in ideology between America and the Soviet Union; capitalism and communism, Joseph Stalin refused to allow free elections in Eastern Europe for a fear of capitalist expansion.

Read more about Joseph Stalin here:

brainly.com/question/903444

#SPJ1

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Figure p12. 4 shows three uniform objects: a rod, a right triangle, and a square. Their masses and their coordinates in meters a
Amiraneli [1.4K]

The center of gravity for the three-objects system is approximately located

at their center of mass.

  • The center of gravity of the three-object system is approximately (2.58, 4.75)

Reasons:

The coordinates of the vertices of the objects and their masses are;

The rod:

Vertices, (2, 7), and (9, 7)

Mass, m₁ = 6.00 kg.

The right triangle;

Vertices; (4, 1), (8, 5), (8, 1)

Mass, m₂ = 3.00 kg.

The square

Vertices; (-5, 5), (-2, 5), (-2, 2), (-5, 2)

Mass, m₃ = 5.00 kg

Required;

The center of gravity for the three-object system.

Solution:

The center of gravity is given by the formula;

\displaystyle X_c =\mathbf{ \frac{X_{c1} \times m_1 +X_{c2} \times m_2 +X_{c3} \times m_3   }{m_1 + m_2 + m_3}}

\displaystyle Y_c =\mathbf{  \frac{Y_{c1} \times m_1 +Y_{c2} \times m_2 +Y_{c3} \times m_3   }{m_1 + m_2 + m_3}}

Where;

X_{c1} = The x-coordinates of the center of the rod = 5.5

X_{c2} = The x-coordinate of the centroid of the triangle  \displaystyle = \frac{4 + 8 + 8}{3} = \frac{20}{3}

X_{c3} = The x-coordinate of the centroid of the square = (-5 - (-2)) ÷ 2 - 2 = -3.5

Y_{c1} = The y-coordinate of the center of the rod = 7

\mathbf{ Y_{c2}} = The y-coordinate of the centroid of the triangle  \displaystyle = \frac{7}{3}

Y_{c3} = The y-coordinate of the centroid of the square = 3.5

Therefore;

\displaystyle X_c = \mathbf{ \frac{5.5 \times 6 +\frac{20}{3} \times 3 +(-3.5) \times 5   }{6+ 3 + 5}} \approx  2.58

\displaystyle Y_c = \mathbf{ \frac{7 \times 6 +\frac{7}{3} \times 3 +3.5 \times 5   }{6+ 3 + 5}} = 4.75

The center of gravity for the three-object system is (X_c, Y_c) ≈ (2.58, 4.75)

Learn more about center of gravity here:

brainly.com/question/6765179

8 0
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