Answer:
He would have a very soggy picture!
OR if you mean the pitcher holds one twelvth of a gallon, he will have 9/12 or 3/4 of a gallon.
OR if you mean the pitcher holds two twelvths of a gallon, he ends up with 9 × 1/6 which is one and a half gallons.
Step-by-step explanation:
Spelling is important! A "picture" could be a drawing, a photograph, or a painting.
"Pitcher" could be a container for pouring liquids or a player who pitches the ball in a baseball game.
I know you wanted math help, but it is difficult to answer if I can't tell whether "to" meant "two" or he filled the pitcher to pour twelvths.
The answer would be A)$679.80
The reason for this is let’s start with the mark up of 10%. Meaning we will add the result of the markup to our first number We would take 1000*.1 which would give us 100.
Add that to the original to give you $1,100.
Then the item was discounted for 40% meaning we take away the result of 1,100*.4 which equals 440. 1100-440=660.
Then taxes are added on to the total so you would do 660*.03 which would give you 19.8
660+19.8 gives you$679.80.
Answer:
5i√10
Step-by-step explanation:
hope this answers your question
:)
Answer:
0.087
Step-by-step explanation:
Given that there were 17 customers at 11:07, probability of having 20 customers in the restaurant at 11:12 am could be computed as:
= Probability of having 3 customers in that 5 minute period. For every minute period, the number of customers coming can be modeled as:
X₅ ~ Poisson (20 (5/60))
X₅ ~ Poisson (1.6667)
Formula for computing probabilities for Poisson is as follows:
P (X=ₓ) = ((<em>e</em>^(-λ)) λˣ)/ₓ!
P(X₅= 3) = ((<em>e</em>^(-λ)) λˣ)/ₓ! = (e^-1.6667)((1.6667²)/3!)
P(X₅= 3) = (2.718^(-1.6667))((2.78)/6)
P(X₅= 3) = (2.718^(-1.6667))0.46
P(X₅= 3) = 0.1889×0.46
P(X₅= 3) = 0.086894
P(X₅= 3) = 0.087
Therefore, the probability of having 20 customers in the restaurant at 11:12 am given that there were 17 customers at 11:07 am is 0.087.
