The term in the expansion:
T ( k+1) = n C k * A^(n-k) * B^k.
In this case: n = 11, k + 1 = 8, so k = 7.
A = x, B = - 3 y
T 8 = 11 C 7 * x^(11-7) * ( - 3 y )^7 =
=( 11 *10 * 9 * 8 * 7 * 6 * 5 ) / ( 7 * 6 * 5 * 4 * 3 * 2 * 1 )* x^4 * ( - 2,187 y^7 ) =
= 330 * ( - 2,187 ) x^4 y^7 = - 721,710 x^4 y^7
Answer: The 8th term in expansion is
Given:
To find:
The product of the polynomials.
Solution:
1. 
Multiply the numerical coefficient and add the powers of x.
2. 
Multiply each term of first polynomial with each term of 2nd polynomial.
Multiply the numerical coefficient and add the powers of x.
3. 
Multiply each term of first polynomial with each term of 2nd polynomial.
Multiply the numerical coefficient and add the powers of x.
Add or subtract like terms together.
The answer for multiplying polynomials:
Answer:
36 sq ft
Step-by-step explanation:
<span>
<span><span>
x
y=2*(0.5)^x
</span><span>-10
2048
</span>
<span>
-9
1024
</span>
<span>
-8
512
</span>
<span>
-7
256
</span>
<span>
-6
128
</span>
<span>
-5
64
</span>
<span>
-4
32
</span>
<span>
-3
16
</span><span>-2
8
</span>
<span>
-1
4
</span>
<span>
0
2
</span>
<span>
1
1
</span>
<span>
2
0.5
</span>
<span>
3
0.25
</span>
<span>
4
0.125
</span>
<span>
5
0.0625
</span>
<span>
6
0.03125
</span>
<span>
7
0.015625
</span>
<span>
8
0.0078125
</span>
<span>
9
0.00390625
</span>
<span>
10
0.00195313
As x goes to negative infinity the function grows to infinity.
As x grows to infinity the function decreases an approximate to zero. </span></span></span>
