H(x) = -4x – 4; Find h(3x)<br><br> please help, I’m confused if it’s -4•3•3 or not

Compare and contrast the solution of |2x + 8| > 6 and the solution of |2x + 8| < 6.

svet-max [94.6K]

Answer:

B.

The solution of |2x + 8| > 6 includes all values that are less than –7 or greater than –1.

The solution of |2x + 8| < 6 includes all values that are greater than –7 and less than –1.

__

Step-by-step explanation:

You can find the solution by "unfolding" the absolute value, then dividing by 2 and subtracting 4:

-6 > 2x +8 > 6 . . . . . read this as -6 is less than 2x+8 or 2x+8 is greater than 6

-3 > x +4 > 3 . . . . . . .divide by 2

-7 > x > -1 . . . . . . . . . solution to the first inequality: x is less than -7 or greater than -1.

___

The solution to the other inequality is identical, except the direction of the comparison is reversed. It is read differently, because the segments overlap, rather than being disjoint.

-7 < x < -1 . . . . . . . . solution to the second inequality: x is greater than -7 and less than -1.

__

These descriptions match choice B.

3 0

3 years ago

EXPAND:

Sladkaya [172]

Answer:

$\displaystyle A) 5\log( {x}^{} ) + 2 \log( {y}^{} )$

Step-by-step explanation:

we would like to expand the following logarithmic expression:

$\displaystyle \log( {x}^{5} {y}^{2} )$

remember the multiplication logarithmic indentity given by:

$\displaystyle \rm \log( \alpha \times \beta ) \iff \log( \alpha ) + \log( \beta )$

so our given expression should be

$\displaystyle \log( {x}^{5} ) + \log( {y}^{2} )$

by exponent logarithmic property we acquire:

$\displaystyle 5\log( {x}^{} ) + 2 \log( {y}^{} )$

hence, our answer is A

5 0

3 years ago

Find the simple interest: Principal: $650 Interest Rate: 14% Time: 4 years

andrew11 [14]

Answer:

292.50 dollars

Step-by-step explanation:

P = 650 is the the principal.

r = 0.09 is the interest rate in decimal form.

t = 5 is the number of years.

i = 650*0.09*5

i = 292.50 is the simple interest.

5 0

2 years ago

Can someone plz help me solved this problem! I’m giving you 10 points! I need help plz help me! Will mark you as brainiest!

sergeinik [125]

Answer:

a). 8(x + a)

b). 8(h + 2x)

Step-by-step explanation:

a). Given function is, f(x) = 8x²

For x = a,

f(a) = 8a²

Now substitute these values in the expression,

$\frac{f(x)-f(a)}{x-a}$ = $\frac{8x^2-8a^2}{x-a}$

= $\frac{8(x^2-a^2)}{(x-a)}$

= $\frac{8(x-a)(x+a)}{(x-a)}$

= 8(x + a)

b). $\frac{f(x+h)-f(x)}{h}$ = $\frac{8(x+h)^2-8x^2}{h}$

= $\frac{8(x^2+h^2+2xh)-8x^2}{h}$

= $\frac{8x^2+8h^2+16xh-8x^2}{h}$

= (8h + 16x)

= 8(h + 2x)

4 0

3 years ago

If sec= 5/3 and the terminal point determined by is in quadrant 4, then

OLga [1]

$\bf sec(\theta)=\cfrac{1}{cos(\theta)}\\\\
-----------------------------\\\\
sec(\theta)=\cfrac{5}{3}\implies \cfrac{1}{cos(\theta)}=\cfrac{5}{3}\implies \cfrac{3}{5}=cos(\theta)
\\\\\\
\textit{now, }\theta\textit{ is in the 4th quadrant}$

so... notice the picture below, the angle in the fourth quadrant
now... notice, the cosine is just the distance the angle makes with the x-axis
so... using the pythagorean theorem, get the opposite side, from that triangle, keeping in mind that, "y" is negative in the 4th quadrant

once you get "y", get any other trigonometry value you need :)

7 0

3 years ago

Read 2 more answers

H(x) = -4x – 4; Find h(3x) please help, I’m confused if it’s -4•3•3 or not