She bought 3 pounds.
work: $80-$57.26 = 22.74 and with 22.74 you divide it by $7.58 and when you divide you get 3
<h2>The chances of receiving two greens are 5/31.</h2>
<em>Given a bag containing four blue, three red, and five green marbles, the total result is:</em>
<em>Total number of balls = 4 + 3 + 5 = 12</em>
<em>If green is chosen first, the chances of picking a green are 5/12.</em>
<em>The probability that the second stone is green is 4/11 if it is picked and not replaced (4 greens remaining)</em>
<em>The chance of earning two greens is 5/12 4/11.</em>
<em>The chance of getting two greens is 20/132.</em>
<em>The chance of earning two greens is 5/31.</em>
<h3>
<em>As a result, the chance of getting two greens is 5/31.</em></h3>
Answer:
$131.88
hope this helps
Step-by-step explanation:
First, "boxes of two sizes" means we can assign variables: Let x = number of large boxes y = number of small boxes "There are 115 boxes in all" means x + y = 115 [eq1] Now, the pounds for each kind of box is: (pounds per box)*(number of boxes) So, pounds for large boxes + pounds for small boxes = 4125 pounds "the truck is carrying a total of 4125 pounds in boxes" (50)*(x) + (25)*(y) = 4125 [eq2] It is important to find two equations so we can solve for two variables. Solve for one of the variables in eq1 then replace (substitute) the expression for that variable in eq2. Let's solve for x: x = 115 - y [from eq1] 50(115-y) + 25y = 4125 [from eq2] 5750 - 50y + 25y = 4125 [distribute] 5750 - 25y = 4125 -25y = -1625 y = 65 [divide both sides by (-25)] There are 65 small boxes. Put that value into either equation (now, which is easier?) to solve for x: x = 115 - y x = 115 - 65 x = 50 There are 50 large boxes.
If I understand the question correctly, 6/10.
