The answer is (3) methyl butane. The isomer means that they have the same chemical formula but different structure. Pentane has five carbon atoms and is alkane. Only methyl butane has five carbon atoms.
Answer:
The volume of nitrogen oxide formed is 35.6L
Explanation:
The reaction of nitric acid with copper is:
Cu(s) + 4HNO₃ → Cu(NO₃)₂ + 2NO₂(g) + 2H₂O(l)
Moles of copper are:
![4.95cm^3\frac{8.95g}{1cm^3} \frac{1mol}{63.55g} = 0.697 moles](https://tex.z-dn.net/?f=4.95cm%5E3%5Cfrac%7B8.95g%7D%7B1cm%5E3%7D%20%5Cfrac%7B1mol%7D%7B63.55g%7D%20%3D%200.697%20moles)
Moles of nitric acid are:
![230mL\frac{1.42g}{mL} \frac{68g}{100g} \frac{1mol}{63.01g}=3.52moles](https://tex.z-dn.net/?f=230mL%5Cfrac%7B1.42g%7D%7BmL%7D%20%5Cfrac%7B68g%7D%7B100g%7D%20%5Cfrac%7B1mol%7D%7B63.01g%7D%3D3.52moles)
As 1 mol of Cu reacts with 4 moles of HNO₃:
0.697 mol Cu × (4mol HNO₃ / 1mol Cu) = 2.79 moles of HNO₃ will react. That means Cu is limiting reactant.
Moles of NO₂ produced are:
0.697 mol Cu × (2mol NO₂ / 1mol Cu) = <em>1.394 moles of NO₂</em>
Using PV = nRT
<em>Where P is pressure (735torr / 760 = 0.967atm); n are moles (1.394mol); R is gas constant (0.082atmL/molK); T is temperature (28.2°C + 273.15 = 301.35K). </em>
Thus, volume is:
V = nRT / P
V = 1.394mol×0.082atmL/molK×301.35K / 0.967atm
V = 35.6L
<em>The volume of nitrogen oxide formed is 35.6L</em>
That is choice A.
The products are different from the reactants.
This may be easy to see - for example when one of the products is precipitated, like when you add BaCL2 to Na2SO4. The BaSO4 formed is insoluble in water and appears as a white precipitate.
The electron dot structure would look like this :
Answer:
C) 2-bromo-1-methylpropane